Simplify Path [LeetCode]

Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"

click to show corner cases.

Corner Cases:

• Did you consider the case where path = "/../"?
  In this case, you should return "/".
• Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
  In this case, you should ignore redundant slashes and return "/home/foo".

Summary: Very careful about corner cases, like "/", "/.", "..".

 class Solution {
 public:
     void handleEntry(vector<string> &path_stack, string path_entry) {
         if(path_entry == "..") {
             if(path_stack.size() > )
                 path_stack.pop_back();
         }else if (path_entry != ".")
                 path_stack.push_back(path_entry);
     }

     string simplifyPath(string path) {
         string simple_path;
         if(path.size() == )
             return simple_path;
         vector<string> path_stack;
         string path_entry;
         for(int i = ; i < path.size(); i ++) {
             if(path_entry.size() ==  && path[i] == '/'){
                 continue;
             }else if (path_entry.size() !=  && path[i] == '/') {
                 handleEntry(path_stack, path_entry);
                 path_entry.clear();
             }else {
                 path_entry.push_back(path[i]);
             }
         }
         if(path_entry.size() > )
             handleEntry(path_stack, path_entry);

         for(string item: path_stack) {
             simple_path += "/";
             simple_path += item;
         }
         if(simple_path.size() == )
             return "/";
         return simple_path;
     }
 };