题目:

Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

代码:

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isBalanced(TreeNode* root)
{
if (!root) return true;
if ( abs(Solution::height(root->left)-Solution::height(root->right)) <= )
{
return Solution::isBalanced(root->left) && Solution::isBalanced(root->right);
}
else
{
return false;
}
}
static int height(TreeNode* p)
{
if (!p) return ;
return max(Solution::height(p->left),Solution::height(p->right))+;
}
};

tips:

第一次刷这leetcode把此题漏掉了。

注意balanced tree是指every node:

(1)判断每个节点left和right深度是否相等

(2)再判断left和right分别是不是balanced的

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