Codeforces Round #561 (Div. 2) A. Silent Classroom(贪心)
A. Silent Classroom
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
There are n students in the first grade of Nlogonia high school. The principal wishes to split the students into two classrooms (each student must be in exactly one of the classrooms). Two distinct students whose name starts with the same letter will be chatty if they are put in the same classroom (because they must have a lot in common). Let x be the number of such pairs of students in a split. Pairs (a,b) and (b,a) are the same and counted only once.
For example, if there are 6 students: “olivia”, “jacob”, “tanya”, “jack”, “oliver” and “jessica”, then:
splitting into two classrooms (“jack”, “jacob”, “jessica”, “tanya”) and (“olivia”, “oliver”) will give x=4 (3 chatting pairs in the first classroom, 1 chatting pair in the second classroom),
splitting into two classrooms (“jack”, “tanya”, “olivia”) and (“jessica”, “oliver”, “jacob”) will give x=1 (0 chatting pairs in the first classroom, 1 chatting pair in the second classroom).
You are given the list of the n names. What is the minimum x we can obtain by splitting the students into classrooms?
Note that it is valid to place all of the students in one of the classrooms, leaving the other one empty.
Input
The first line contains a single integer n (1≤n≤100) — the number of students.
After this n lines follow.
The i-th line contains the name of the i-th student.
It is guaranteed each name is a string of lowercase English letters of length at most 20. Note that multiple students may share the same name.
Output
The output must consist of a single integer x — the minimum possible number of chatty pairs.
Examples
inputCopy
4
jorge
jose
oscar
jerry
outputCopy
1
inputCopy
7
kambei
gorobei
shichiroji
kyuzo
heihachi
katsushiro
kikuchiyo
outputCopy
2
inputCopy
5
mike
mike
mike
mike
mike
outputCopy
4
Note
In the first sample the minimum number of pairs is 1. This can be achieved, for example, by putting everyone except jose in one classroom, and jose in the other, so jorge and jerry form the only chatty pair.
In the second sample the minimum number of pairs is 2. This can be achieved, for example, by putting kambei, gorobei, shichiroji and kyuzo in one room and putting heihachi, katsushiro and kikuchiyo in the other room. In this case the two pairs are kambei and kyuzo, and katsushiro and kikuchiyo.
In the third sample the minimum number of pairs is 4. This can be achieved by placing three of the students named mike in one classroom and the other two student
#include<stdio.h>
#include<string.h>
int main()
{
static int kk[26];
int n, c, k, ans;
scanf("%d", &n);
while (n--)
{
static char s[32];
scanf("%s", s);
kk[s[0] - 'a']++;
}
ans = 0;
for (c = 0; c < 26; c++)
{
k = kk[c] / 2;
ans += k * (k - 1) / 2 + (kk[c] - k) * (kk[c] - k - 1) / 2;
}
printf("%d\n", ans);
return 0;
}
Codeforces Round #561 (Div. 2) A. Silent Classroom(贪心)的更多相关文章
- Codeforces Round #561 (Div. 2) A. Silent Classroom
链接:https://codeforces.com/contest/1166/problem/A 题意: There are nn students in the first grade of Nlo ...
- Codeforces Round #561 (Div. 2) C. A Tale of Two Lands
链接:https://codeforces.com/contest/1166/problem/C 题意: The legend of the foundation of Vectorland talk ...
- Codeforces Round #561 (Div. 2) B. All the Vowels Please
链接:https://codeforces.com/contest/1166/problem/B 题意: Tom loves vowels, and he likes long words with ...
- Codeforces Round 561(Div 2)题解
这是一场失败的比赛. 前三题应该是随便搞的. D有点想法,一直死磕D,一直WA.(赛后发现少减了个1……) 看E那么多人过了,猜了个结论交了真过了. 感觉这次升的不光彩……还是等GR3掉了洗掉这次把, ...
- Codeforces Round #561 (Div. 2) E. The LCMs Must be Large(数学)
传送门 题意: 有 n 个商店,第 i 个商店出售正整数 ai: Dora 买了 m 天的东西,第 i 天去了 si 个不同的个商店购买了 si 个数: Dora 的对手 Swiper 在第 i 天去 ...
- Codeforces Round #561 (Div. 2)
C. A Tale of Two Lands 题意: 给出 n 个数,问有多少点对(x,y)满足 |x-y| ≤ |x|,|y| ≤ |x+y|: (x,y) 和 (y,x) 表示一种答案: 题解: ...
- Codeforces Round #561 (Div. 2) A Tale of Two Lands 【二分】
A Tale of Two Lands 题目链接(点击) The legend of the foundation of Vectorland talks of two integers xx and ...
- Codeforces Round #180 (Div. 2) D. Fish Weight 贪心
D. Fish Weight 题目连接: http://www.codeforces.com/contest/298/problem/D Description It is known that th ...
- Codeforces Round #180 (Div. 2) A. Snow Footprints 贪心
A. Snow Footprints 题目连接: http://www.codeforces.com/contest/298/problem/A Description There is a stra ...
随机推荐
- DG磁盘分区提示错误
文章更新于:2020-02-26 一.当你使用 DG 分区遇到错误时 1.错误复现 2.解决办法 以管理员身份打开cmd 运行 chkdsk /f /x g:(这里的 g 替换成你要检查的盘符) 然后 ...
- rest_framework-序列化-1
序列化 定义模型类 from django.db import models # Create your models here. class StuModel(models.Model): SEX_ ...
- MySQL入门,第一部分,全局管理命令
1.连接数据库命令 mysql -h localhost -u root -p 回车后输入密码即可连接到数据库 2.显示当前mysql管理系统中的所有数据库 SHOW DATABASES; 3.显示当 ...
- linux美化网址
参考博文地址 https://blog.csdn.net/qq_42527676/article/details/91356154 https://www.opendesktop.org/ Dash ...
- 汇编刷题:求1000H单元开始的10个无符号字节数的最大值(本题放入了BL寄存器)
DATA SEGMENT ORG 1000H INFO DB 1,2,3,4,5,70H,71H,72H,80H,92H MAX DB 00H DATA ENDS CODE SEGMENT ASSUM ...
- 多数据源系统接入mybatis-plus, 实现动态数据源、动态事务。
目录: 实现思想 导入依赖.配置说明 代码实现 问题总结 一.实现思想 接手一个旧系统,SpringBoot 使用的是纯粹的 mybatis ,既没有使用规范的代码生成器,也没有使用 JPA 或者 m ...
- jQuery extend()和jQuery.fn.extend()区别和详解
1.认识jQuery extend()和jQuery.fn.extend() jQuery的API手册中,extend方法挂载在jQuery和jQuery.fn两个不同对象上方法,但在jQuery内部 ...
- 利用SSIS进行SharePoint 列表数据的ETL
好几年前写了一篇<SSIS利用Microsoft Connector for Oracle by Attunity组件进行ETL!>,IT技术真是日新月异,这种方式对于新的SQL SERV ...
- stand up meeting 12/21/2015
part 组员 工作 工作耗时/h 明日计划 工作耗时/h UI 冯晓云 完成PDF UI主页面的页面切换功能,待完善 4 完善 ...
- Mysql数据导入导出功能(设置及使用)
使用Mysql自带的outfile语法,将查询结果导成excel格式. 1.OUTFILE介绍及常见问题解决: )查询数据导出成csv 直接使用mysql导出csv方法 我们可以使用 into out ...