An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.

Input

Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.

Output

For each problem instance, output consists of one line. This line should be one of the following three:

Sorted sequence determined after xxx relations: yyy...y. 
Sorted sequence cannot be determined. 
Inconsistency found after xxx relations.

where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence.

Sample Input

4 6
A<B
A<C
B<C
C<D
B<D
A<B
3 2
A<B
B<A
26 1
A<Z
0 0

Sample Output

Sorted sequence determined after 4 relations: ABCD.
Inconsistency found after 2 relations.
Sorted sequence cannot be determined.
代码:
#include<cstdio>
#include<iostream>
#include<cstring>
#include<algorithm>
#include<queue>
#include<stack>
#include<vector>
#include<map>
#include<cmath>
const int maxn=1e5+;
typedef long long ll;
using namespace std;
vector<int>vec[];
int n,m;
int du[];
int chu[];
int du1[];
int flag;
vector<int>ans1;
void Tpsort()
{
priority_queue<int,vector<int>,greater<int> >q;
priority_queue<int>q1; int s=;
for(int t=;t<n;t++)
{
if(chu[t]==&&du[t]==)
{
s=;
}
}
for(int t=;t<n;t++)
{
du1[t]=du[t];
}
for(int t=;t<n;t++)
{
if(du1[t]==)
{
q.push(t);
q1.push(t);
}
}
vector<int>ans,ans2;
while(!q.empty())
{
int now=q.top();
int now2=q1.top();
q.pop();
q1.pop();
ans.push_back(now);
ans2.push_back(now2);
for(int t=;t<vec[now].size();t++)
{
int next=vec[now][t];
du1[next]--;
if(du1[next]==)
{
q.push(next);
q1.push(next);
}
}
}
if(ans.size()!=n)
{
flag=;
}
// cout<<ans.size()<<" "<<s<<endl; if(ans.size()==n&&s==)
{
int sss=;
for(int t=;t<ans.size();t++)
{
if(ans[t]!=ans2[t])
{
sss=;
}
}
if(sss==)
{
flag=;
for(int t=;t<ans.size();t++)
{
ans1.push_back(ans[t]);
}
} } }
int main()
{ while(cin>>n>>m)
{
if(n==&&m==)
{
break;
}
for(int t=;t<n;t++)
{
vec[t].clear();
}
char str[];
memset(du,,sizeof(du));
memset(chu,,sizeof(chu));
flag=;
int ss=;
int k;
ans1.clear();
for(int t=;t<=m;t++)
{
scanf("%s",str);
vec[str[]-'A'].push_back(str[]-'A');
du[str[]-'A']++;
chu[str[]-'A']++;
if(ss)
{
continue;
}
Tpsort();
if(flag==)
{
printf("Inconsistency found after %d relations.\n",t);
ss=;
}
else if(flag==)
{
ss=;
printf("Sorted sequence determined after %d relations: ",t);
for(int j=;j<n;j++)
{
printf("%c",ans1[j]+'A');
}
printf(".\n"); }
}
if(ss==)
puts("Sorted sequence cannot be determined."); }
return ;
}

Sorting It All Out (拓扑排序+思维)的更多相关文章

  1. ACM: poj 1094 Sorting It All Out - 拓扑排序

    poj 1094 Sorting It All Out Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%lld & ...

  2. poj 1094 Sorting It All Out (拓扑排序)

    http://poj.org/problem?id=1094 Sorting It All Out Time Limit: 1000MS   Memory Limit: 10000K Total Su ...

  3. [poj1094]Sorting It All Out_拓扑排序

    Sorting It All Out poj-1094 题目大意:给出一些字符串之间的大小关系,问能否得到一个唯一的字符串序列,满足权值随下标递增. 注释:最多26个字母,均为大写. 想法:显然,很容 ...

  4. POJ1094 Sorting It All Out —— 拓扑排序

    题目链接:http://poj.org/problem?id=1094 Sorting It All Out Time Limit: 1000MS   Memory Limit: 10000K Tot ...

  5. ZOJ 4124 拓扑排序+思维dfs

    ZOJ - 4124Median 题目大意:有n个元素,给出m对a>b的关系,问哪个元素可能是第(n+1)/2个元素,可能的元素位置相应输出1,反之输出0 省赛都过去两周了,现在才补这题,这题感 ...

  6. POJ 1094:Sorting It All Out拓扑排序之我在这里挖了一个大大的坑

    Sorting It All Out Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 29984   Accepted: 10 ...

  7. CF思维联系--CodeForces -214C (拓扑排序+思维+贪心)

    ACM思维题训练集合 Furik and Rubik love playing computer games. Furik has recently found a new game that gre ...

  8. [ACM_模拟] POJ 1094 Sorting It All Out (拓扑排序+Floyd算法 判断关系是否矛盾或统一)

    Description An ascending sorted sequence of distinct values is one in which some form of a less-than ...

  9. nyoj349 poj1094 Sorting It All Out(拓扑排序)

    nyoj349   http://acm.nyist.net/JudgeOnline/problem.php?pid=349poj1094   http://poj.org/problem?id=10 ...

随机推荐

  1. 【NOIP2015】斗地主 题解(DFS+贪心)

    题目描述 牛牛最近迷上了一种叫斗地主的扑克游戏.斗地主是一种使用黑桃.红心.梅花.方片的AAA到KKK加上大小王的共545454张牌来进行的扑克牌游戏.在斗地主中,牌的大小关 系根据牌的数码表示如下: ...

  2. Phthon环境搭建

    一,官网去下载 https://www.python.org/downloads/ 二,安装 三,验证python 四.IPython IPython 是一个 python 的交互式 shell,比默 ...

  3. Vue组件通信之子传父

    子组件向父组件通信主要通过自定义事件实现. 这里我记录一个小例子来帮助自己记忆. 通过点击子组件的按钮去执行父组件的函数并使用子组件传来的数据. 子组件定义如下: <template id=&q ...

  4. JavaFX桌面应用-为什么应用老是“未响应”

    日常使用软件的过程中,偶尔会遇到软件突然卡住,再点击几次就变成"未响应"的情况. 在JavaFX应用中同样也会出现这种情况,在开发过程中应该尽量避免这种情况的出现. >> ...

  5. C#LeetCode刷题-并查集

    并查集篇 # 题名 刷题 通过率 难度 128 最长连续序列   39.3% 困难 130 被围绕的区域   30.5% 中等 200 岛屿的个数   38.4% 中等 547 朋友圈   45.1% ...

  6. C#算法设计之知识储备

    前言 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/669 访问. 算法的讨论具有一定的规则,其中也包含一些不成文的约定 ...

  7. 微博AnalysisQl动态数据视图元数据设计

    前言 目前,AnalysisQl 数据视图的元数据(维度.指标.指标计算器)需要通过代码(API)或资源文件的形式硬编码,应用启动时,按照声明的顺序依次注册.这种模式下,数据视图是 静态 的,任何一项 ...

  8. js中几种常用的数组处理方法的总结

    一.filter()用法 功能:用于筛选数组中满足条件的元素,返回一个筛选后的新数组. <script> $(function(){ var arr = [1,-2,3,4,-5]; va ...

  9. 封装react antd的表格table组件

    封装组件是为了能在开发过程中高度复用功能和样式相似的组件,以便我们只关注于业务逻辑层的处理,提高开发效率,提高逼格,降低代码重复率,降低劳动时间,减少加班的可能. 本次组件的封装采用了函数式组件即无状 ...

  10. 【Gin-API系列】Gin中间件之日志模块(四)

    日志是程序开发中必不可少的模块,同时也是日常运维定位故障的最重要环节之一.一般日志类的操作包括日志采集,日志查询,日志监控.日志统计等等.本文,我们将介绍日志模块在Gin中的使用. Golang如何打 ...