Android LruCache源码简介
package android.util; import java.util.LinkedHashMap;
import java.util.Map; /**
* A cache that holds strong references to a limited number of values. Each time
* a value is accessed, it is moved to the head of a queue. When a value is
* added to a full cache, the value at the end of that queue is evicted and may
* become eligible for garbage collection.
* Cache保存一个强引用来限制内容数量,每当Item被访问的时候,此Item就会移动到队列的头部。
* 当cache已满的时候加入新的item时,在队列尾部的item会被回收。
* <p>If your cached values hold resources that need to be explicitly released,
* override {@link #entryRemoved}.
* 如果你cache的某个值需要明确释放,重写entryRemoved()
* <p>If a cache miss should be computed on demand for the corresponding keys,
* override {@link #create}. This simplifies the calling code, allowing it to
* assume a value will always be returned, even when there's a cache miss.
* 如果key相对应的item丢掉啦,重写create().这简化了调用代码,即使丢失了也总会返回。
* <p>By default, the cache size is measured in the number of entries. Override
* {@link #sizeOf} to size the cache in different units. For example, this cache
* is limited to 4MiB of bitmaps: 默认cache大小是测量的item的数量,重写sizeof计算不同item的
* 大小。
* <pre> {@code
* int cacheSize = 4 * 1024 * 1024; // 4MiB
* LruCache<String, Bitmap> bitmapCache = new LruCache<String, Bitmap>(cacheSize) {
* protected int sizeOf(String key, Bitmap value) {
* return value.getByteCount();
* }
* }}</pre>
*
* <p>This class is thread-safe. Perform multiple cache operations atomically by
* synchronizing on the cache: <pre> {@code
* synchronized (cache) {
* if (cache.get(key) == null) {
* cache.put(key, value);
* }
* }}</pre>
*
* <p>This class does not allow null to be used as a key or value. A return
* value of null from {@link #get}, {@link #put} or {@link #remove} is
* unambiguous: the key was not in the cache.
* 不允许key或者value为null
* 当get(),put(),remove()返回值为null时,key相应的项不在cache中
*/
public class LruCache<K, V> {
private final LinkedHashMap<K, V> map; /** Size of this cache in units. Not necessarily the number of elements. */
private int size; //已经存储的大小
private int maxSize; //规定的最大存储空间 private int putCount; //put的次数
private int createCount; //create的次数
private int evictionCount; //回收的次数
private int hitCount; //命中的次数
private int missCount; //丢失的次数 /**
* @param maxSize for caches that do not override {@link #sizeOf}, this is
* the maximum number of entries in the cache. For all other caches,
* this is the maximum sum of the sizes of the entries in this cache.
*/
public LruCache(int maxSize) {
if (maxSize <= 0) {
throw new IllegalArgumentException("maxSize <= 0");
}
this.maxSize = maxSize;
this.map = new LinkedHashMap<K, V>(0, 0.75f, true);
} /**
* Returns the value for {@code key} if it exists in the cache or can be
* created by {@code #create}. If a value was returned, it is moved to the
* head of the queue. This returns null if a value is not cached and cannot
* be created. 通过key返回相应的item,或者创建返回相应的item。相应的item会移动到队列的头部,
* 如果item的value没有被cache或者不能被创建,则返回null。
*/
public final V get(K key) {
if (key == null) {
throw new NullPointerException("key == null");
} V mapValue;
synchronized (this) {
mapValue = map.get(key);
if (mapValue != null) {
hitCount++; //命中
return mapValue;
}
missCount++; //丢失
} /*
* Attempt to create a value. This may take a long time, and the map
* may be different when create() returns. If a conflicting value was
* added to the map while create() was working, we leave that value in
* the map and release the created value.
* 如果丢失了就试图创建一个item
*/ V createdValue = create(key);
if (createdValue == null) {
return null;
} synchronized (this) {
createCount++;//创建++
mapValue = map.put(key, createdValue); if (mapValue != null) {
// There was a conflict so undo that last put
//如果前面存在oldValue,那么撤销put()
map.put(key, mapValue);
} else {
size += safeSizeOf(key, createdValue);
}
} if (mapValue != null) {
entryRemoved(false, key, createdValue, mapValue);
return mapValue;
} else {
trimToSize(maxSize);
return createdValue;
}
} /**
* Caches {@code value} for {@code key}. The value is moved to the head of
* the queue.
*
* @return the previous value mapped by {@code key}.
*/
public final V put(K key, V value) {
if (key == null || value == null) {
throw new NullPointerException("key == null || value == null");
} V previous;
synchronized (this) {
putCount++;
size += safeSizeOf(key, value);
previous = map.put(key, value);
if (previous != null) { //返回的先前的value值
size -= safeSizeOf(key, previous);
}
} if (previous != null) {
entryRemoved(false, key, previous, value);
} trimToSize(maxSize);
return previous;
} /**
* @param maxSize the maximum size of the cache before returning. May be -1
* to evict even 0-sized elements.
* 清空cache空间
*/
private void trimToSize(int maxSize) {
while (true) {
K key;
V value;
synchronized (this) {
if (size < 0 || (map.isEmpty() && size != 0)) {
throw new IllegalStateException(getClass().getName()
+ ".sizeOf() is reporting inconsistent results!");
} if (size <= maxSize) {
break;
} Map.Entry<K, V> toEvict = map.eldest();
if (toEvict == null) {
break;
} key = toEvict.getKey();
value = toEvict.getValue();
map.remove(key);
size -= safeSizeOf(key, value);
evictionCount++;
} entryRemoved(true, key, value, null);
}
} /**
* Removes the entry for {@code key} if it exists.
* 删除key相应的cache项,返回相应的value
* @return the previous value mapped by {@code key}.
*/
public final V remove(K key) {
if (key == null) {
throw new NullPointerException("key == null");
} V previous;
synchronized (this) {
previous = map.remove(key);
if (previous != null) {
size -= safeSizeOf(key, previous);
}
} if (previous != null) {
entryRemoved(false, key, previous, null);
} return previous;
} /**
* Called for entries that have been evicted or removed. This method is
* invoked when a value is evicted to make space, removed by a call to
* {@link #remove}, or replaced by a call to {@link #put}. The default
* implementation does nothing.
* 当item被回收或者删掉时调用。改方法当value被回收释放存储空间时被remove调用,
* 或者替换item值时put调用,默认实现什么都没做。
* <p>The method is called without synchronization: other threads may
* access the cache while this method is executing.
*
* @param evicted true if the entry is being removed to make space, false
* if the removal was caused by a {@link #put} or {@link #remove}.
* true---为释放空间被删除;false---put或remove导致
* @param newValue the new value for {@code key}, if it exists. If non-null,
* this removal was caused by a {@link #put}. Otherwise it was caused by
* an eviction or a {@link #remove}.
*/
protected void entryRemoved(boolean evicted, K key, V oldValue, V newValue) {} /**
* Called after a cache miss to compute a value for the corresponding key.
* Returns the computed value or null if no value can be computed. The
* default implementation returns null.
* 当某Item丢失时会调用到,返回计算的相应的value或者null
* <p>The method is called without synchronization: other threads may
* access the cache while this method is executing.
*
* <p>If a value for {@code key} exists in the cache when this method
* returns, the created value will be released with {@link #entryRemoved}
* and discarded. This can occur when multiple threads request the same key
* at the same time (causing multiple values to be created), or when one
* thread calls {@link #put} while another is creating a value for the same
* key.
*/
protected V create(K key) {
return null;
} private int safeSizeOf(K key, V value) {
int result = sizeOf(key, value);
if (result < 0) {
throw new IllegalStateException("Negative size: " + key + "=" + value);
}
return result;
} /**
* Returns the size of the entry for {@code key} and {@code value} in
* user-defined units. The default implementation returns 1 so that size
* is the number of entries and max size is the maximum number of entries.
* 返回用户定义的item的大小,默认返回1代表item的数量,最大size就是最大item值
* <p>An entry's size must not change while it is in the cache.
*/
protected int sizeOf(K key, V value) {
return 1;
} /**
* Clear the cache, calling {@link #entryRemoved} on each removed entry.
* 清空cacke
*/
public final void evictAll() {
trimToSize(-1); // -1 will evict 0-sized elements
} /**
* For caches that do not override {@link #sizeOf}, this returns the number
* of entries in the cache. For all other caches, this returns the sum of
* the sizes of the entries in this cache.
*/
public synchronized final int size() {
return size;
} /**
* For caches that do not override {@link #sizeOf}, this returns the maximum
* number of entries in the cache. For all other caches, this returns the
* maximum sum of the sizes of the entries in this cache.
*/
public synchronized final int maxSize() {
return maxSize;
} /**
* Returns the number of times {@link #get} returned a value that was
* already present in the cache.
*/
public synchronized final int hitCount() {
return hitCount;
} /**
* Returns the number of times {@link #get} returned null or required a new
* value to be created.
*/
public synchronized final int missCount() {
return missCount;
} /**
* Returns the number of times {@link #create(Object)} returned a value.
*/
public synchronized final int createCount() {
return createCount;
} /**
* Returns the number of times {@link #put} was called.
*/
public synchronized final int putCount() {
return putCount;
} /**
* Returns the number of values that have been evicted.
* 返回被回收的数量
*/
public synchronized final int evictionCount() {
return evictionCount;
} /**
* Returns a copy of the current contents of the cache, ordered from least
* recently accessed to most recently accessed. 返回当前cache的副本,从最近最少访问到最多访问
*/
public synchronized final Map<K, V> snapshot() {
return new LinkedHashMap<K, V>(map);
} @Override public synchronized final String toString() {
int accesses = hitCount + missCount;
int hitPercent = accesses != 0 ? (100 * hitCount / accesses) : 0;
return String.format("LruCache[maxSize=%d,hits=%d,misses=%d,hitRate=%d%%]",
maxSize, hitCount, missCount, hitPercent);
}
}
转自http://blog.csdn.net/linghu_java/article/details/8574102
Android LruCache源码简介的更多相关文章
- Android——LruCache源码解析
以下针对 Android API 26 版本的源码进行分析. 在了解LruCache之前,最好对LinkedHashMap有初步的了解,LruCache的实现主要借助LinkedHashMap.Lin ...
- 【转】Android LruCache源码介绍
本文来源:转载自: http://blog.csdn.net/linghu_java/article/details/8574102 package android.util; import java ...
- 【安卓本卓】Android系统源码篇之(一)源码获取、源码目录结构及源码阅读工具简介
前言 古人常说,“熟读唐诗三百首,不会作诗也会吟”,说明了大量阅读诗歌名篇对学习作诗有非常大的帮助.做开发也一样,Android源码是全世界最优秀的Android工程师编写的代码,也是A ...
- 【流媒体开发】VLC Media Player - Android 平台源码编译 与 二次开发详解 (提供详细800M下载好的编译源码及eclipse可调试播放器源码下载)
作者 : 韩曙亮 博客地址 : http://blog.csdn.net/shulianghan/article/details/42707293 转载请注明出处 : http://blog.csd ...
- Appium Android Bootstrap源码分析之控件AndroidElement
通过上一篇文章<Appium Android Bootstrap源码分析之简介>我们对bootstrap的定义以及其在appium和uiautomator处于一个什么样的位置有了一个初步的 ...
- Android HandlerThread 源码分析
HandlerThread 简介: 我们知道Thread线程是一次性消费品,当Thread线程执行完一个耗时的任务之后,线程就会被自动销毁了.如果此时我又有一 个耗时任务需要执行,我们不得不重新创建线 ...
- Android应用源码航空订票软件客户端
功能分类:其他 支持平台:Android 运行环境:Android 开发语言:Java 开发工具:Eclipse 源码大小:1.76MB 下载地址:http://w ...
- Android Choreographer 源码分析
Choreographer 的作用主要是配合 Vsync ,给上层 App 的渲染提供一个稳定的 Message 处理的时机,也就是 Vsync 到来的时候 ,系统通过对 Vsync 信号周期的调整, ...
- 还怕问源码?Github上神级Android三方源码解析手册,已有7.6 KStar
或许对于许多Android开发者来说,所谓的Android工程师的工作"不过就是用XML实现设计师的美术图,用JSON解析服务器的数据,再把数据显示到界面上"就好了,源码什么的,看 ...
随机推荐
- Django项目:CRM(客户关系管理系统)--65--55PerfectCRM实现CRM客户报名状态颜色变化
# kingadmin.py # ————————04PerfectCRM实现King_admin注册功能———————— from crm import models #print("ki ...
- Html 重要单词归纳
1.translate(x,y)平移2.scale(x,y)缩放3.fillstyle填充4.linearGradient(xstart,ystart,xend,yend)渐变5.move to 将光 ...
- PAT甲级——A1015 Reversible Primes
A reversible prime in any number system is a prime whose "reverse" in that number system i ...
- [Day6] Nginx 进阶模块
一. 使用变量防盗链referer模块 功能:通过验证referer请求头是否合法,来拒绝非正常的网站访问我们站点的资源 思路:通过referer模块,用invaild_refereri变量根据配置判 ...
- Django之数据库连接与建模
Django数据库链接(这里以Mysql为例) 需要准备 Django1.10 pip install django==1.10 -i https://pypi.tuna.tsinghua.edu.c ...
- VC++1.5太伟大了
功能样样俱全,一点不比现在的VS系列差 VC++1.5全貌,虽然很古老,但是已经可以了. 新建的文档试图,多文档工程,很像样 文档试图,单文档工程,已经非常像样了,和记事本差不多了 这是资源编辑器,寒 ...
- MFC 双缓存绘图
在SDI应用程序中,当我们需要时刻动态刷新界面的时候,如果我们一直使用,UpdateAllView()那么就会出现屏幕不停闪烁.闪屏非常严重,特别是一直在动态刷新的时候.并且在闪屏的过程中 我们根本就 ...
- 在rabbitmq操作页面上添加队列、交换器及绑定示图
1.添加队列 2.添加交换器 3.绑定
- 【python之路40】Python 作用域
python的作用域与javaScript是一样的,参考:http://www.cnblogs.com/sunshuhai/p/9112578.html 一.python是以函数作为作用域的 if 1 ...
- 小希的迷宫 HDU - 1272 (并查集)
思路: 当图中的集合(连通子图)个数为1并且边数等于顶点数-1(即改图恰好为一棵生成树)时,输出Yes. 此题的坑:(1) 如果只输入0 0算作一组数据的话答案应该输出Yes (2) 输入数据可能并不 ...