Longest Substring Without Repeating Characters

Given a string, find the length of the longest substring
without repeating characters.

Examples:

Given "abcabcbb", the answer is "abc", which the length is 3.

Given "bbbbb", the answer is "b", with the length of 1.

Given "pwwkew", the answer is "wke", with the length of 3.
Note that the answer must be a substring,
"pwke" is a subsequence and not a substring.

 /*************************************************************************
> File Name: LeetCode003.c
> Author: Juntaran
> Mail: JuntaranMail@gmail.com
> Created Time: Tue 17 May 2016 17:10:02 PM CST
************************************************************************/ /************************************************************************* Longest Substring Without Repeating Characters Given a string, find the length of the longest substring
without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of 1. Given "pwwkew", the answer is "wke", with the length of 3.
Note that the answer must be a substring,
"pwke" is a subsequence and not a substring. ************************************************************************/ #include "stdio.h" /* 8ms */
int lengthOfLongestSubstring(char* s)
{
int n = strlen(s); if( n <= )
{
return n;
} int i = , j = ;
int maxLen = ;
int exist[] = { };
while( j < n )
{
if( exist[s[j]] )
{
maxLen = maxLen>(j-i) ? maxLen : (j-i);
while( s[i] != s[j] )
{
exist[s[i]] = ;
i++;
}
i++;
j++;
}
else
{
exist[s[j]] = ;
j++;
}
}
maxLen = maxLen>(n-i) ? maxLen : (n-i);
return maxLen;
} /* 36ms */
int lengthOfLongestSubstring2(char* s)
{
int len = ;
int p= , q=, i; for( q=; q<strlen(s); q++ )
{
for( i=p; i<q; i++ )
{
if( s[q] == s[i] )
{
if( q-p > len ) len = q-p;
p = i+;
}
}
}
len = len>q-p?len:q-p;
return len;
} int main()
{
char* s = "abccab";
int ret = lengthOfLongestSubstring(s);
printf("%d\n", ret); return ;
}

LeetCode 3的更多相关文章

  1. 我为什么要写LeetCode的博客?

    # 增强学习成果 有一个研究成果,在学习中传授他人知识和讨论是最高效的做法,而看书则是最低效的做法(具体研究成果没找到地址).我写LeetCode博客主要目的是增强学习成果.当然,我也想出名,然而不知 ...

  2. LeetCode All in One 题目讲解汇总(持续更新中...)

    终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance ...

  3. [LeetCode] Longest Substring with At Least K Repeating Characters 至少有K个重复字符的最长子字符串

    Find the length of the longest substring T of a given string (consists of lowercase letters only) su ...

  4. Leetcode 笔记 113 - Path Sum II

    题目链接:Path Sum II | LeetCode OJ Given a binary tree and a sum, find all root-to-leaf paths where each ...

  5. Leetcode 笔记 112 - Path Sum

    题目链接:Path Sum | LeetCode OJ Given a binary tree and a sum, determine if the tree has a root-to-leaf ...

  6. Leetcode 笔记 110 - Balanced Binary Tree

    题目链接:Balanced Binary Tree | LeetCode OJ Given a binary tree, determine if it is height-balanced. For ...

  7. Leetcode 笔记 100 - Same Tree

    题目链接:Same Tree | LeetCode OJ Given two binary trees, write a function to check if they are equal or ...

  8. Leetcode 笔记 99 - Recover Binary Search Tree

    题目链接:Recover Binary Search Tree | LeetCode OJ Two elements of a binary search tree (BST) are swapped ...

  9. Leetcode 笔记 98 - Validate Binary Search Tree

    题目链接:Validate Binary Search Tree | LeetCode OJ Given a binary tree, determine if it is a valid binar ...

  10. Leetcode 笔记 101 - Symmetric Tree

    题目链接:Symmetric Tree | LeetCode OJ Given a binary tree, check whether it is a mirror of itself (ie, s ...

随机推荐

  1. 第二百四十三天 how can I 坚持

    制定的计划完成不了了,好多问题啊.又想当然了,晚上加了会班. 今天雾霾好严重,一出地铁大裤衩怎么没了.雾霾爆表啊. 还好现在刮大风了. 准备看<芈mi月传>了. 睡觉.

  2. homework-07

    终于等到了一次难度相对比较小的问题,只要读完提问题就好,但又不得不说自己真的很菜,且不说C++掌握的不好,连英文也比较差,导致读的非常吃力,不过我还是坚持读完了四篇英文文章,大致意思是可以了解的,但是 ...

  3. PID入门的十五个基本概念

    PID调节系统PID功能由PID调节器或DCS系统内部功能程序模块实现,了解与PID调节相关的一些基本概念,有助于PID入门新手快速熟悉调节器应用,在自动调节系统中成功整定PID参数.1.被调量被调量 ...

  4. uniPanel特效

    function beforeInit(sender){ sender.layout='accordion'; Ext.apply (sender, {title:'供应链',style:'text- ...

  5. SQLite的37个核心函数

    转载:http://www.feiesoft.com/00012/ abs(X) abs(X)返回 X 的绝对值. Abs(X) returns NULL if X is NULL. Abs(X) r ...

  6. CodeForces 732C Sanatorium (if-else)

    题意:某人去旅游,记录了一共吃了多少顿饭,早中晚,但是有可能缺少,问你最少缺少了多少顿. 析:每把三个数排序,然后再一一对比,肯定是以最大数为主,其他两个肯定是缺少了. 代码如下: #pragma c ...

  7. libevent的使用方法--回显服务器的简单实例

    #include <event.h> #include <sys/types.h> #include <sys/socket.h> #include <net ...

  8. Qt + CURL + mimetic 发送邮件(带附件)

    使用了大名鼎鼎的CURL 开源库,以及mimetic开源库. CURL支持N多协议.功能超强,但是不能直接发邮件附件,需要自己拼mime.太麻烦,于是乎~~ mimetic主要用于构造邮件mimeti ...

  9. [0.1]Plan of kidsearch

    To be honest, it's not pretty easy to complete the project. So we have to sort out ideas first. In t ...

  10. 电脑右键新建文本文档(txt)消失的解决办法

    其实只需要一个注册表就可以了 下载地址http://pan.baidu.com/s/1hr7r0fM 拿走不谢! 注册表的内容是这样的,你也可以新建一个文件把后缀名改成.reg然后把下面的内容copy ...