A+B Coming

Problem Description

Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal.
^_^

 

Input

Input may contain multiple test cases. Each case
contains A and B in one line.
A, B are hexadecimal number.
Input
terminates by EOF.

 

Output

Output A+B in decimal number in one line.

 

Sample Input

1 9

A B

a b

 

Sample Output

10

21

21

 

 #include <stdio.h>
 #include <string.h>
 #include <ctype.h>
 #include <math.h>

 int decimal(char s[]);

 int main(){
     char s1[];
     char s2[];
     int number1;
     int number2;

     while(scanf("%s%s",s1,s2)!=EOF){
         number1=decimal(s1);
         number2=decimal(s2);

         printf("%d\n",number1+number2);

     }

     return ;
 }

 int decimal(char s[]){
     int result=;
     int i;
     int length;
     int temp;

     length=strlen(s);

     for(i=length-;i>=;i--){
         if(isdigit(s[i]))
             temp=s[i]-'';

         else if(s[i]=='A' || s[i]=='a')
             temp=;

         else if(s[i]=='B' || s[i]=='b')
             temp=;

         else if(s[i]=='C' || s[i]=='c')
             temp=;

         else if(s[i]=='D' || s[i]=='d')
             temp=;

         else if(s[i]=='E' || s[i]=='e')
             temp=;

         else if(s[i]=='F' || s[i]=='f')
             temp=;

         result+=temp*pow(,length--i);
     }

     return result;
 }