Programmable current source requires no power supply
Engineering labs are usually equipped with various power supplies, voltmeters, function generators, and oscilloscopes. One piece of equipment missing from many such labs, however, is a current source. This omission is unfortunate, because a current source is useful for creating I-V (current-versus-voltage) curves, charging and discharging batteries, preloading power supplies, and many other applications.
The circuit in Figure 1 is an easy-to-build, easy-to-use, low-cost current source. It comprises three sections of BCD (binary-coded-decimal) switches, a three-terminal adjustable regulator, a handful of 1%-tolerant resistors, and a National Semiconductor LM317 three-terminal adjustable regulator. All newer National Semiconductor regulators are of the low-dropout type, which is unsuitable for this application. The switches short their four outputs to a common terminal based on the digit setting of the switch.
The circuit operates as follows: Assume that the red terminal in Figure 1 connects to a 5V power supply and that the black terminal connects to the power supply’s ground. Assume that the middle digit (labeled 10 to 90 mA) gets set to two and that the other two digits get set to zero. The BCD switch connects a 62Ω resistor from the LM317’s output to adjust pins. The LM317 forces 1.25V across the 62Ω resistor, causing 20 mA to flow from the output pin through the resistor, and to the black terminal of the current source. The circuit maintains this regulation provided that the input voltage remains 3 to 40V.
To construct the current source, you should either use a heat sink for the LM317 or build the circuit into a die-cast aluminum housing, which acts as the heat sink. Isolate the LM317 from the heat sink using a thermally conductive isolation pad and a shoulder washer. You determine the resistors’ values by starting with the base-resistance value, 1.24 kΩ. Then, simply use parallel values to determine the successive resistors’ values. For example, two 1.24-kΩ resistors in parallel yield 620Ω, four 1.24-kΩ resistors in parallel yield 310Ω, and so on. Using this approach with ¼W resistors ensures that the highest current resistors do not overheat. For example, eight 12.4Ω, ¼W resistors yield 1.55Ω resistance and dissipate only 1W with a peak capability of 2W.
The performance of the circuit is about 2% accurate. You can achieve higher accuracy with hand-selected resistors. The output impedance for lower currents is more than 1 MΩ but drops to approximately 250 kΩ at 200 mA.

Programmable current source requires no power supply的更多相关文章
- Level-shifting nixes need for dual power supply
The AD736 true-rms-to-dcconverter is useful for many applications that require precise calculation o ...
- Linux power supply class hacking
/*************************************************************************** * Linux power supply cl ...
- Linux power supply class(1)_软件架构及API汇整【转】
1. 前言 power supply class为编写供电设备(power supply,后面简称PSY)的驱动提供了统一的框架,功能包括: 1)抽象PSY设备的共性,向用户空间提供统一的API. 2 ...
- C4K Power supply failed?
故障log: %C4K_IOSMODPORTMAN-4-POWERSUPPLYBAD: Power supply 2 has failed or been turned off 在单机的情况下,我们可 ...
- Bug搬运工-CSCux99539:Intermittent error message "Power supply 2 failed or shutdown"
Description Symptom:Following error messages will be seen intermittently.%PFMA-2-PS_FAIL: Power supp ...
- Current Sourcing (拉電流) and Current Sinking(灌電流)
Current Sourcing and Sinking Current sourcing and sinking is often mentioned in relation to electron ...
- Current-sense monitor and MOSFET boost output current
A previous Design Idea describes a programmable current source that used a three-terminal National S ...
- System and method for dynamically adjusting to CPU performance changes
FIELD OF THE INVENTION The present invention is related to computing systems, and more particularly ...
- Driving proportional valves from microcontroller
Driving proportional valves from microcontroller I am looking to drive a current regulated proportio ...
随机推荐
- hdu 4347 The Closest M Points (kd树)
版权声明:本文为博主原创文章,未经博主允许不得转载. hdu 4347 题意: 求k维空间中离所给点最近的m个点,并按顺序输出 . 解法: kd树模板题 . 不懂kd树的可以先看看这个 . 不多说, ...
- 垃圾回收算法与 JVM 垃圾回收器综述(转)
垃圾回收算法与 JVM 垃圾回收器综述 我们常说的垃圾回收算法可以分为两部分:对象的查找算法与真正的回收方法.不同回收器的实现细节各有不同,但总的来说基本所有的回收器都会关注如下两个方面:找出所有的存 ...
- HTML文件编码
为了防止中文乱码,一般在网页头文件中加入 <meta http-equiv="Content-Type" content="text/html; charset=u ...
- Ps钢笔操作技巧
鼠标左键单击=新建锚点:Ctrl+鼠标左键=移动锚点/移动调节点: Alt+鼠标左键=锚点/角点转换: 方向键=微调锚点位置: shift+鼠标左键=新建水平/垂直锚点:Ctrl+Alt+鼠标左键=选 ...
- AC日记——830A - Office Keys
思路: 背包: 代码: #include <cmath> #include <cstdio> #include <cstring> #include <ios ...
- 【严蔚敏】【数据结构(C语言版)】 求n的阶乘
阶乘函数为: 使用递归即可求得. #include <stdio.h> #include <stdlib.h> int Fact(int m){ ) ; ); //递归求阶乘 ...
- 面试题12:打印1到最大的n位数(大数问题)
面试题是关于n位整数并且没有限定n的取值范围,或者是输入任意大小的整数,那么这个题目就很可能需要考虑大数问题.字符串是一个简单的.有效的表示大数的方法 这题比较难,用递归表达全排列,数字每一位都可能是 ...
- 在microsoft/dotnet:2.0.0-sdk中安装vim编辑器
在Docker中安装了dotnetcore 2.0.0 的sdk,没有发现可用的编辑器,该sdk是基于debian:stretch构建的,以前没玩过debian,因为CentOS玩的多一些所以对vim ...
- chrome浏览器使用HTML5预览图片
chrome浏览器对HTML5支持的较好,使用HTML5的File相关的api,可以实现前台页面在选定图片后,不上传即可预览.代码如下: 1.前台代码,使用<input type="f ...
- 使用matlab表示“段数不确定”的分段函数
示例函数: 分段函数f(x)的段数为数组a的长度减1,在表达f(x)时,不能直接使用a的长度5-1=4. 方法1: 先计算每个间隔点的函数值f(a2),f(a3),f(a4),再循环表示f(x). f ...