经典union的使用

一个用户下广告位  某一天有收入和支出  有支出不一定有收入  有收入不一定有支出  下例为按用户查询 sanhao 下的信息

支出如下：

收入如下：

按天进行查询，例如查询：

得到结果如下：

使用一般的按日期左关联，会出现错误。

正确的使用如下，把每个表的收入或者支出补全 为0，然后union合并 再进行分组合并

select rownum rn,mm0.accesstime,nvl(mm1.inall,0) inall
                               ,nvl(mm1.outall,0) outall,mm1.placeid
                               ,decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) profit
                               ,decode(inall,0,'-', to_char(round((decode(mm1.inall,null,0,mm1.inall)-decode(mm1.outall,null,0,mm1.outall) )/inall,4)*100)||'%') proRate
                              
                               from
                        (
                            select column_value as accesstime from table(fn_split('2013-10-12,2013-10-13,2013-10-14',',') )
                        ) mm0,
                        (                        
                            select accesstime,placeid,sum(inall) inall,sum(outall2) outall  from
                            (     
                                  --包广告位付款
                                  select 0 inall,to_char(rd.accounttime,'yyyy-mm-dd') as accesstime,rd.placeid ,decode(sum(rd.paysum),null,0,sum(rd.paysum)) outall2
                                  from ad_paidrecord rd
                                  inner join ad_place pl on rd.placeid=pl.placeid and pl.ismonthly=1
                                  where rd.placeid!=0--包广告位
                                        and pl.ismonthly=1
                                        and rd.rectype in(0,2)
                                        and rd.accounttime>= to_date('2013-10-12','yyyy-mm-dd')
                                        and rd.accounttime<= to_date('2013-10-14','yyyy-mm-dd')--根据记账日期（小的日期）
                                        --and (i_placeid=-1 or rd.placeid=i_placeid)
                                        and (rd.webuserid='sanhao' )
                                  group by rd.accounttime,rd.placeid
                                  union
                                  --总收入                              
                                  select sum(v.income)inall,to_char(v.accesstime,'yyyy-mm-dd') as accesstime,v.placeid,0
                                  from v_placeincome v
                                  where v.accesstime >= to_date('2013-10-12','yyyy-mm-dd')
                                        and v.accesstime <=  to_date('2013-10-14','yyyy-mm-dd')
                                      --  and (i_placeid=-1 or v.placeid=i_placeid)
                                        and v.ismonthly=1
                                        and (v.webuserid='sanhao')
                                  group by accesstime,placeid
                                )
                                group by accesstime,placeid
                         )  mm1                      
                       where  mm0.accesstime=mm1.accesstime(+)
                          and (inall>0 or (nvl(mm1.outall,0))>0)
                          order by placeid,mm0.accesstime asc;