The statement of this problem is very simple: you are to determine how many squares of the chessboard can be attacked by a knight standing alone on the board. Recall that a knight moves two squares forward (horizontally or vertically in any direction) and then one square sideways (perpedicularly to the first direction).

Input

The first line contains the number N of test cases, 1 ≤ N ≤ 100. Each of the following N lines contains a test: two characters. The first character is a lowercase English letter from 'a' to 'h' and the second character is an integer from 1 to 8; they specify the rank and file of the square at which the knight is standing.

Output

Output N lines. Each line should contain the number of the squares of the chessboard that are under attack by the knight.

Sample

input output
3
a1
d4
g6
2
8
6
Problem Author: folklore Problem Source: Fifth High School Children Programming Contest, Ekaterinburg, March 02, 2002
// Ural Problem 1197. Lonesome Knight
// Verdict: Accepted
// Submission Date: 10:31:16 14 Jan 2014
// Run Time: 0.015s
//
// 版权所有(C)acutus。(mail: acutus@126.com)
// 博客:http://www.cnblogs.com/acutus/
// [解题方法]
// 简单题,直接按题意判断即可 #include<stdio.h> int countNumber(int i, int j)
{
int count = ;
if((i - ) >= ) {
if((j - ) >= ) count++;
if((j + ) <= ) count++;
}
if((i - ) >= ) {
if((j - ) >= ) count++;
if((j + ) <= ) count++;
}
if((i + ) <= ) {
if((j - ) >= ) count++;
if((j + ) <= ) count++;
}
if((i + ) <= ) {
if((j - ) >= ) count++;
if((j + ) <= ) count++;
}
return count;
} void solve()
{
int N, n;
char c;
scanf("%d", &N);
getchar();
while(N--) {
scanf("%c%d", &c, &n);
getchar();
printf("%d\n",countNumber(c - 'a' + , n));
}
} int main()
{
solve();
return ;
}

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