Binary Tree: 0到2个子节点;

Binary Search Tree: 所有左边的子节点 < node自身 < 所有右边的子节点;

1. Full类型: 除最下面一层外, 每一层都有两个子节点;

2. Complete类型: 除最下面一层外为Full类型, 但是最下面一层最所有子节点靠左;

3. Balanced类型: 左右两个子树的长度相差小于等于一;

/**
* Definition of TreeNode:
* public class TreeNode {
* public int val;
* public TreeNode left, right;
* public TreeNode(int val) {
* this.val = val;
* this.left = this.right = null;
* }
* }
*/
public class Solution {
/**
* @param root: The root of binary tree.
* @return: True if this Binary tree is Balanced, or false.
*/
int checkHeight(TreeNode root){
if(root == null) return -; int leftHeight = checkHeight(root.left);
if(leftHeight == Integer.MIN_VALUE) return Integer.MIN_VALUE; int rightHeight = checkHeight(root.right);
if(rightHeight == Integer.MIN_VALUE) return Integer.MIN_VALUE; int heightDiff = leftHeight - rightHeight;
if(Math.abs(heightDiff) > ){
return Integer.MIN_VALUE;
}else{
return Math.max(leftHeight, rightHeight) + ;
}
}
public boolean isBalanced(TreeNode root) {
return checkHeight(root) != Integer.MIN_VALUE; // write your code here
}
}

traverse: 遍历; recursion: 递归(反复用自身); iteration: 迭代(循环);

3种遍历:

1. inorder: 左, node自身, 右(最左下角的node为第一个, 最右下角的node为最后一个);

2. preorder: node自身, 左, 右(node自身为第一个, 最右下角的node为最后一个);

3. postorder: 左, 右, node自身(最左下角的node为第一个, node自身为最后一个);

class Node {
int val;
Node left;
Node right; public Node(int v) {
this.val = v;
}
} public class BST { public static void inorder(Node node) {
// 1. return condition
if(node == null) return; // 2. process
inorder(node.left); System.out.println(node.val); inorder(node.right);
} public static void preorder(Node node) {
if(node == null) return; System.out.println(node.val); preorder(node.left); preorder(node.right);
} public static void postorder(Node node) { if(node == null) return; postorder(node.left); postorder(node.right); System.out.println(node.val);
} public static void main(String[] args) {
// TODO Auto-generated method stub
Node root = buildTree(); inorder(root);
} public static Node buildTree() {
Node ten = new Node();
Node one = new Node();
Node fifteen = new Node();
Node five = new Node(); five.left = one;
ten.left = five;
ten.right = fifteen; return ten;
}
}

CCI4.4/LintCode Balanced Binary Tree, Binary Tree, Binary Search Tree的更多相关文章

  1. LintCode Validate Binary Search Tree

    Validate Binary Search Tree Given a binary tree, determine if it is a valid binary search tree (BST) ...

  2. Lintcode: Remove Node in Binary Search Tree

    iven a root of Binary Search Tree with unique value for each node. Remove the node with given value. ...

  3. Lintcode: Search Range in Binary Search Tree

    Given two values k1 and k2 (where k1 < k2) and a root pointer to a Binary Search Tree. Find all t ...

  4. LintCode题解之Search Range in Binary Search Tree

    1.题目描述 2.问题分析 首先将二叉查找树使用中序遍历的方式将元素放入一个vector,然后在vector 中截取符合条件的数字. 3.代码 /** * Definition of TreeNode ...

  5. Lintcode: Insert Node in a Binary Search Tree

    Given a binary search tree and a new tree node, insert the node into the tree. You should keep the t ...

  6. 【Lintcode】087.Remove Node in Binary Search Tree

    题目: Given a root of Binary Search Tree with unique value for each node. Remove the node with given v ...

  7. 【Lintcode】011.Search Range in Binary Search Tree

    题目: Given two values k1 and k2 (where k1 < k2) and a root pointer to a Binary Search Tree. Find a ...

  8. 【Lintcode】095.Validate Binary Search Tree

    题目: Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is define ...

  9. [数据结构]——二叉树(Binary Tree)、二叉搜索树(Binary Search Tree)及其衍生算法

    二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现 ...

随机推荐

  1. 不经过 App store 的安装方式(转)

    所有安装到真机(非越狱)的应用(可以是 .app ,也可以是 .ipa ,只要编译时选的是编译成 Arm 的就好..app 转 .ipa 只需要一条命令) 都必须经过证书签名.证书主要有三大种: 企业 ...

  2. ICML历年Best Papers

    作者:我爱机器学习原文链接:ICML历年Best Papers ICML (Machine Learning)(1999-2016) 2016 Dueling Network Architecture ...

  3. React Native 组件样式测试

    View组件默认样式(注意默认flexDirection:'column') {flexGrow:0,flexShrink:0,flexBasis:'auto',flexDirection:'colu ...

  4. 黑马程序员——OC语言基础语法 面向对象的思想

    Java培训.Android培训.iOS培训..Net培训.期待与您交流! (以下内容是对黑马苹果入学视频的个人知识点总结)(一)基础语法 1)关键字 @interface.@implementati ...

  5. php的__clone __call

    (1) __clone方法在一个对象赋值给另外的一个对象的时候自动调用 <?php class A { public $a = "aa"; public $b = 10; f ...

  6. convertdate

    sample date 2015-09-10 00:00:00 2015-09-09 00:00:00.000 expect iso date, add time zone 2015-09-10T00 ...

  7. JAVA String,StringBuffer与StringBuilder的区别??

    String 字符串常量StringBuffer 字符串变量(线程安全)StringBuilder 字符串变量(非线程安全) 简要的说, String 类型和 StringBuffer 类型的主要性能 ...

  8. ajax 中boolean值技巧

    // 利用判断 数据重复 function checkId () { var flag = true; $.ajax({ url: "", type: "post&quo ...

  9. [蟒蛇菜谱]Python函数参数传递最佳实践

    将函数作为参数传递,同时将该函数需要的参数一起传递.可参考threading.Timer的处理方式: class threading.Timer(interval, function, args=[] ...

  10. 查出重复的数据---------oracle

    select chcod, count(1) from a group by chcod having count(1) > 1