Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2.

Note:

  1. The length of both num1 and num2 is < 5100.
  2. Both num1 and num2 contains only digits 0-9.
  3. Both num1 and num2 does not contain any leading zero.
  4. You must not use any built-in BigInteger library or convert the inputs to integer directly.

题目

如题

思路

1. while loop will run as long as there is character left in nums1, nums2 or carry

2. from right to left, each character is converted to integer

3. If the shorter string is exhausted first, the value will be forced to `0` as default

代码

 class Solution {
public String addStrings(String num1, String num2) {
//how many digits will be added? three! 1st from num1Array, 2nd from num2Array, 3rd from carry
int carry = 0;
int num1Len = num1.length()-1;
int num2Len = num2.length()-1; // StringBuilder can append and remove, more efficient
StringBuilder sb = new StringBuilder(); //while loop will run as long as there is character left in nums1, nums2 or carry
while(num1Len >= 0 || num2Len >=0 || carry >0){
// from right to left, each character is converted to integer
// If the shorter string is exhausted first, the value will be forced to `0` as default
int update1 = num1Len>=0 ? num1.charAt(num1Len--)-'0' :0;
int update2 = num2Len>=0 ? num2.charAt(num2Len--)-'0' :0;
int sum = update1 + update2 + carry;
sb.insert(0,sum%10);
carry = sum/10;
}
return sb.toString();
}
}

[leetcode]415. Add Strings字符串相加的更多相关文章

  1. [LeetCode] 415. Add Strings 字符串相加

    Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. ...

  2. 415 Add Strings 字符串相加

    给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和.注意:    num1 和num2 的长度都小于 5100.    num1 和num2 都只包含数字 0-9.    num1 和 ...

  3. [LeetCode] 415 Add Strings && 67 Add Binary && 43 Multiply Strings

    这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/pro ...

  4. 36. leetcode 415. Add Strings

    415. Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum ...

  5. [LeetCode] Add Strings 字符串相加

    Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. ...

  6. LeetCode - 415. Add Strings

    Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. ...

  7. leetcode 415 两个字符串相加

    string addstring(string s1,string s2) { string ans=""; ; ,j=s2.length()-;i>=||j>=;i- ...

  8. 【leetcode】415. Add Strings

    problem 415. Add Strings solution: class Solution { public: string addStrings(string num1, string nu ...

  9. [LeetCode] 43. Multiply Strings 字符串相乘

    Given two non-negative integers num1 and num2represented as strings, return the product of num1 and  ...

随机推荐

  1. PHP 序列化变量的 4 种方法

    摘自: PHP 序列化变量的 4 种方法 http://www.iteye.com/news/25668

  2. js判断各种浏览器

    <script type="text/javascript"> if (navigator.appName.indexOf("Microsoft Intern ...

  3. 【基础知识六】支持向量机SVM

    开发库: libsvm, liblinear      GitHub地址 SVM难点:核函数选择 一.基本问题 找到约束参数ω和b,支持向量到(分隔)超平面的距离最大:此时的分隔超平面称为“最优超平面 ...

  4. 生存分析与R

    生存分析与R 2018年05月19日 19:55:06 走在码农路上的医学狗 阅读数:4399更多 个人分类: R语言   版权声明:本文为博主原创文章,未经博主允许不得转载. https://blo ...

  5. 35. CentOS-6.3安装拼音输入法

    安装方法: su root yum install "@Chinese Support"      // 安装中文输入法 exit 装好后,在“系统-->首选项”就会看到有“ ...

  6. Java中3种代理总结(示例代码见之前文章)

    1.JDK静态代理 业务接口 接口的实现类 代理类,实现接口,并扩展实现类的功能 ### 2.JDK动态代理 业务接口 实现了业务接口的业务类 实现了InvocationHandler接口的handl ...

  7. 值得推荐的C/C++开源框架和库

    值得推荐的C/C++开源框架和库  转自:http://www.cnblogs.com/lidabo/p/5514155.html   - 1. Webbench Webbench是一个在Linux下 ...

  8. & 运算

    var f:uint; var e:uint; f=uint.MAX_VALUE; e=1<<31; trace(f,e,f&e); //output:4294967295 214 ...

  9. sql查询分析器中显示行号

    -- 工具-> -- 选项-> -- 文本编辑器-> -- 所有语言-> -- 常规-> -- 显示-> -- 行号

  10. Git reset head revert 回滚

    Overview 涉及Git一些日常操作 :) 基础知识 <Pro Git>至少了解branch,commit的概念,及基本的原理 Git常用魔法 存档:master代码回滚方法 我是QA ...