Given a non-negative integer, you could swap two digits at most once to get the maximum valued number. Return the maximum valued number you could get.

Example 1:

Input: 2736
Output: 7236
Explanation: Swap the number 2 and the number 7.

Example 2:

Input: 9973
Output: 9973
Explanation: No swap.

Note:

  1. The given number is in the range [0, 108]

Approach #1: Math. [Java]

class Solution {
public int maximumSwap(int num) {
char[] digits = Integer.toString(num).toCharArray();
int[] buckets = new int[10];
for (int i = 0; i < digits.length; ++i)
buckets[digits[i]-'0'] = i; for (int i = 0; i < digits.length; ++i) {
for (int j = 9; j > digits[i]-'0'; --j) {
if (buckets[j] > i) {
char temp = digits[i];
digits[i] = digits[buckets[j]];
digits[buckets[j]] = temp;
return Integer.valueOf(new String(digits));
}
}
} return num;
}
}

  

Analysis:

https://leetcode.com/problems/maximum-swap/discuss/107068/Java-simple-solution-O(n)-time

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