【LeetCode】680. Valid Palindrome II

Difficulty:easy

 More:【目录】LeetCode Java实现

Description

https://leetcode.com/problems/valid-palindrome-ii/

Given a non-empty string s, you may delete at most one character. Judge whether you can make it a palindrome.

Example 1:

Input: "aba"
Output: True

Example 2:

Input: "abca"
Output: True
Explanation: You could delete the character 'c'.

Intuition

1.Make use of two pointers.

Solution

    public boolean validPalindrome(String s) {
        for(int i = 0, j = s.length()-1; i < j; i++,j--){
            if(s.charAt(i) != s.charAt(j))
                return isPalindrome(s, i, j-1) || isPalindrome(s, i+1, j);
        }
        return true;
    }

    private boolean isPalindrome(String s, int i, int j){
        while(i < j){
            if(s.charAt(i++) != s.charAt(j--))
                return false;
        }
        return true;
    }

　　

Complexity

Time complexity : O(n)

Space complexity : O(1)

What I've learned

1. It's important to learn and make use of the method isPalindrome() 

 More:【目录】LeetCode Java实现