通过实例解释LinuxC下argc,argc[]的意义

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LinuxC下argc,argv[ ]的意义

参考了http://blog.csdn.net/followingturing/article/details/7707584

还是根据实例来进行说明：

 #include<stdio.h>
 #include<stdlib.h>

 int main(int argc,char *argv[])
 {
     if(argc== || argc>)
     {
         printf("Please input the name of the file
                 you want to edit, for example:./edit fillen\n");
         printf("argv[0] is %s\n",argv[]);
     } 

     if(argc==)
     {
         printf("Now EDIT %s\n",argv[]);
         printf("argv[0] is %s\n",argv[]);
         printf("argv[1] is %s\n",argv[]);
     } 

     exit();
 }

• 通过gcc生成可执行文件edit如下：
  
• 运行文件edit：./edit,如下：
  
• 运行文件edit，并输入file.txt: ./edit file.txt,如下：
  

结论：

1. argc 为外部命令参数的个数，因此

   输入命令./edit时，argc==1;
   输入命令./edit file.txt时，argc==2；

2. argv[]为存储的命令，其中argv[0]即为可执行文件名；
   

   输入命令./edit时,argv[0]=="./edit";
   输入命令./edit file.txt时，argv[0]=="./edit",argv[1]=="file.txt";

2017-2-4 23:10;20