ural1855 Trade Guilds of Erathia
Trade Guilds of Erathia
Memory limit: 64 MB
Input
- “change a b d”: the fee for travelling along each route segment between cities a and bchanged by d gold coins (if d is positive, the fee increased; if d is negative, the fee decreased);
- “establish a b”: a new guild which is present in all cities between a and b was established.
All numbers are integers; 1 ≤ a < b ≤ n; −10 000 ≤ d ≤ 10 000. Cities are numbered in the order they are located along the route: from Bracada to Deyja. The fee for travelling along a segment was never larger than 10 000 gold coins, otherwise merchants would protest. Of course, the fee was always non-negative. Before the first royal order changing the fee, it is equal to zero for all route segments.
Output
Sample
| input | output |
|---|---|
4 5 |
1.00000000 |
分析:设询问区间为[l,r],第k条路编号为k+1;
则第k条路的贡献为(k-l)*(r-k+1)*cost[k];
展开后即[-k*k+(l+1+r)*k-l-l*r]*cost[k];
线段树单点维护好cost[k],k*cost[k],k*k*cost[k]即可;
注意爆int;
代码:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define mod 1000000007
#define inf 0x3f3f3f3f
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
#define pii pair<int,int>
#define Lson L, mid, rt<<1
#define Rson mid+1, R, rt<<1|1
const int maxn=1e5+;
using namespace std;
ll gcd(ll p,ll q){return q==?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=;while(q){if(q&)f=f*p;p=p*p;q>>=;}return f;}
int n,m,k;
char op[];
ll ans[];
ll gao(int p)
{
return (ll)p*(p+)*(*p+)/;
}
struct Node
{
ll sum,sum1,sum2,lazy;
} T[maxn<<]; void PushUp(int rt)
{
T[rt].sum = T[rt<<].sum + T[rt<<|].sum;
T[rt].sum1 = T[rt<<].sum1 + T[rt<<|].sum1;
T[rt].sum2 = T[rt<<].sum2 + T[rt<<|].sum2;
} void PushDown(int L, int R, int rt)
{
int mid = (L + R) >> ;
ll t = T[rt].lazy; T[rt<<].sum += t * (mid - L + );
T[rt<<|].sum += t * (R - mid); T[rt<<].sum1 += t * (mid - L + )*(mid + L)/;
T[rt<<|].sum1 += t * (R - mid)*(R + mid +)/; T[rt<<].sum2 += t * (gao(mid)-gao(L-));
T[rt<<|].sum2 += t * (gao(R)-gao(mid)); T[rt<<].lazy += t;
T[rt<<|].lazy += t;
T[rt].lazy = ;
} void Update(int l, int r, ll v, int L, int R, int rt)
{
if(l==L && r==R)
{
T[rt].lazy += v;
T[rt].sum += v * (R - L + );
T[rt].sum1 += v * (R - L + )*(R + L)/;
T[rt].sum2 += v * (gao(R)-gao(L-));
return ;
}
int mid = (L + R) >> ;
if(T[rt].lazy) PushDown(L, R, rt);
if(r <= mid) Update(l, r, v, Lson);
else if(l > mid) Update(l, r, v, Rson);
else
{
Update(l, mid, v, Lson);
Update(mid+, r, v, Rson);
}
PushUp(rt);
} void Query(int l, int r, int L, int R, int rt)
{
if(l==L && r== R)
{
ans[]+=T[rt].sum;
ans[]+=T[rt].sum1;
ans[]+=T[rt].sum2;
return;
}
int mid = (L + R) >> ;
if(T[rt].lazy) PushDown(L, R, rt);
if(r <= mid) Query(l, r, Lson);
else if(l > mid) Query(l, r, Rson);
else Query(l, mid, Lson) , Query(mid + , r, Rson);
}
int main()
{
int i,j;
scanf("%d%d",&n,&m);
while(m--)
{
int a,b,c;
scanf("%s",op);
if(op[]=='c')
{
scanf("%d%d%d",&a,&b,&c);
Update(a+,b,(ll)c,,n,);
}
else
{
scanf("%d%d",&a,&b);
ans[]=ans[]=ans[]=;
Query(a+,b,,n,);
printf("%.10f\n",(double)(-ans[]+(a+b+)*ans[]-(a+(ll)a*b)*ans[])/(b-a)/(b-a+)*);
}
}
//system("Pause");
return ;
}
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