Java for LeetCode 063 Unique Paths II
Follow up for "Unique Paths":
Now consider if some obstacles are added to the grids. How many unique paths would there be?
An obstacle and empty space is marked as 1 and 0 respectively in the grid.
For example,
There is one obstacle in the middle of a 3x3 grid as illustrated below.
[
[0,0,0],
[0,1,0],
[0,0,0]
]
The total number of unique paths is 2.
Note: m and n will be at most 100.
解题思路:
本题如果使用上题中的解法一,将会非常复杂,因此我们修改解法二即可,JAVA实现如下:
public int uniquePathsWithObstacles(int[][] obstacleGrid) {
int[] v = new int[obstacleGrid[0].length];
for (int i = 0; i < v.length; i++)
if (obstacleGrid[0][i] == 0)
v[i] = 1;
else
break;
for (int i = 1; i < obstacleGrid.length; i++) {
if (obstacleGrid[i][0] == 1)
v[0] = 0;
for (int j = 1; j < v.length; j++)
if (obstacleGrid[i][j] == 1)
v[j] = 0;
else
v[j] += v[j - 1];
}
return v[v.length - 1];
}
Java for LeetCode 063 Unique Paths II的更多相关文章
- LeetCode 63. Unique Paths II不同路径 II (C++/Java)
题目: A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...
- [Leetcode Week12]Unique Paths II
Unique Paths II 题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/unique-paths-ii/description/ Descrip ...
- 【leetcode】Unique Paths II
Unique Paths II Total Accepted: 22828 Total Submissions: 81414My Submissions Follow up for "Uni ...
- 【LeetCode】063. Unique Paths II
题目: Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. H ...
- Java for LeetCode 062 Unique Paths
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- [LeetCode] 63. Unique Paths II 不同的路径之二
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- leetcode 63. Unique Paths II
Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. How m ...
- 【题解】【矩阵】【回溯】【Leetcode】Unique Paths II
A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). The ...
- leetcode 【 Unique Paths II 】 python 实现
题目: Follow up for "Unique Paths": Now consider if some obstacles are added to the grids. H ...
随机推荐
- Linux Systemcall Int0x80方式、Sysenter/Sysexit Difference Comparation
目录 . 系统调用简介 . Linux系统调用实现方式的演进 . 通过INT 0x80中断方式进入系统调用 . 通过sysenter指令方式直接进入系统调用 . sysenter/sysexit编程示 ...
- IPC机制
转:http://blog.chinaunix.net/uid-26125381-id-3206237.html IPC 三种通信机制 2012-05-13 17:23:55 最近看了,IPC三种通 ...
- 深入浅出Redis04使用Redis数据库(lists类型)
一 lists类型及操作 List是一个链表结构,主要功能是push,pop,获取一个范围的所有值等等,操作中key理解为链表的名字. Redis的list类型其实就是一个每个子元素都是sring类 ...
- emmet使用 及 notepadd++ emmet的安装
emmet的使用的参考文章:http://www.cnblogs.com/sussski/p/3544744.html html:4s.html:4t.html:5或! +.>.^:层次 *.@ ...
- 批处理:echo的用法
批处理:echo的用法 若要用 echo 命令显示一条命令,可用下述语法: echo [message] 参数 ON|OFF 指定是否允许命令的回显.若要显示当前的 ECHO 的设置,可使用不带 ...
- WebSocket 基本函数
1.构造函数 WebSocket(char *host); 创建一个websocket对象,接受一个参数以ws://靠头,就像发起一个HTTP请求一样用http://开头 var ws=new W ...
- MySQL的left join中on与where的区别
关于 “A LEFT JOIN B ON 条件表达式” 的一点提醒 ON 条件(“A LEFT JOIN B ON 条件表达式”中的ON)用来决定如何从 B 表中检索数据行,即使on中包含有A表中的列 ...
- 实现ajax
啊打发 <script type="text/javascript" src="js/jquery-1.8.3.min.js"></scrip ...
- Cannot find class [org.apache.commons.dbcp.BasicDataSource]
错误:Cannot find class [org.apache.commons.dbcp.BasicDataSource] 原因:缺少commons-dbcp.jar
- NBUT1541 Rainwater 题解
http://cdn.ac.nbutoj.com/Problem/view.xhtml?id=1541 When rain, nocLyt discovered a magical phenomeno ...