Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and set.

get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
set(key, value) - Set or insert the value if the key is not
already present. When the cache reached its capacity, it should
invalidate the least recently used item before inserting a new item.

思路:Hashmap+double-linked list.

Hashmap: key是已给的key,value是ListNode的地址

double-linked list:当链表中某元素要被删除或提到head时,双向链表都方便进行操作

class LRUCache{
private:
/*double-linked list*/
struct ListNode{
ListNode * prev;
ListNode * next;
int key;
int value;
ListNode(int _key, int _value):key(_key), value(_value), prev(NULL), next(NULL){}
}; /*move the node to the head of liest*/
void change2TopPriority(ListNode* listNode){
if(head==listNode) return; //special case: it's the head
listNode->prev->next = listNode->next;
if(listNode->next) listNode->next->prev = listNode->prev;
else tail = tail->prev; //special case: it's the tail
listNode->prev = NULL;
listNode->next = head;
head->prev = listNode;
head = head->prev;
}
public:
LRUCache(int capacity) {
listNodeMap.clear();
this->capacity = capacity;
head = NULL;
tail = NULL;
} int get(int key) {
if(listNodeMap.find(key)!=listNodeMap.end()){
change2TopPriority(listNodeMap[key]);
return listNodeMap[key]->value;
}
else return -;
} void set(int key, int value) {
if(listNodeMap.find(key)==listNodeMap.end()){ // ket not exist
if(listNodeMap.size()==capacity){ // reach the capacity
//erase least used data
listNodeMap.erase(tail->key);
ListNode * tmp = tail;
if(head == tail) { //special case: capacity=1
head = tail = NULL;
}
else{
tail = tail->prev;
tail->next = NULL;
}
delete tmp;
}
//insert new node
ListNode * newNode = new ListNode(key,value);
if(!head){ //special case: first node in the list
head = tail = newNode;
}
else{
head->prev = newNode;
newNode->next = head;
head = head->prev;
}
listNodeMap[key]=newNode;
}
else{ //key already exists
listNodeMap[key]->value = value;
change2TopPriority(listNodeMap[key]);
}
}
private:
unordered_map<int,ListNode*> listNodeMap; //hashmap
ListNode* head; //head of double linked list
ListNode* tail; //tail of double linked list
int capacity; //capacity of CRU
};

146. LRU Cache (List, HashTable)的更多相关文章

  1. leetcode 146. LRU Cache 、460. LFU Cache

    LRU算法是首先淘汰最长时间未被使用的页面,而LFU是先淘汰一定时间内被访问次数最少的页面,如果存在使用频度相同的多个项目,则移除最近最少使用(Least Recently Used)的项目. LFU ...

  2. [LeetCode] 146. LRU Cache 最近最少使用页面置换缓存器

    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...

  3. Java for LeetCode 146 LRU Cache 【HARD】

    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...

  4. leetcode 146. LRU Cache ----- java

    esign and implement a data structure for Least Recently Used (LRU) cache. It should support the foll ...

  5. leetcode@ [146] LRU Cache (TreeMap)

    https://leetcode.com/problems/lru-cache/ Design and implement a data structure for Least Recently Us ...

  6. 146. LRU Cache

    题目: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the ...

  7. 【LeetCode】146. LRU Cache

    LRU Cache Design and implement a data structure for Least Recently Used (LRU) cache. It should suppo ...

  8. [LeetCode] 146. LRU Cache 近期最少使用缓存

    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...

  9. [LC] 146. LRU Cache

    Design and implement a data structure for Least Recently Used (LRU) cache. It should support the fol ...

随机推荐

  1. 优化RequireJS项目(合并与压缩)

    关于RequireJS已经有很多文章介绍过了.这个工具可以将你的JavaScript代码轻易的分割成苦 干个模块(module)并且保持你的代码模块化与易维护性.这样,你将获得一些具有互相依赖关系的J ...

  2. requirejs 到底有什么好处?

    无论是在backbone时代,还是angularjs 时代 我都用过requirejs, 后来慢慢全都去掉了, 因为在前端开发requirejs 感觉没有带来任何实质性的好处. 从几个方面说说我的感受 ...

  3. textArea中的maxlength是无效的 解决办法

    --------------------------------------------------------------------------------------   <s:texta ...

  4. zufeoj NO.1(结构体简单题)

    NO.1 时间限制: 1 Sec  内存限制: 128 MB提交: 457  解决: 172[提交][状态][讨论版] 题目描述 所谓NO.1,就是所有成绩都排在第一的同学,我们假设每个人只有理科,文 ...

  5. Android软键盘弹出将底部栏顶上去并不会挤压界面

    界面需要,找到了一种不需要去设置android:windowSoftInputMode属性的解决keyboard和layout不适问题 有关设置android:windowSoftInputMode的 ...

  6. mydumper 找不到libmysqlclient.so.20

    报错信息: mydumper: error while loading shared libraries: libmysqlclient.so.20: cannot open shared objec ...

  7. css 定位position总结

    在CSS中,Position 属性经常会用到,主要是绝对定位和相对定位,简单的使用都没有问题,尤其嵌套起来,就会有些混乱,今记录总结一下,防止久而忘之. CSS position 属性值: absol ...

  8. Servlet的复习

    Servlet概述 在JavaWeb阶段,使用Servlet是很经常的是事情,Servlet作为MVC中控制器(C)的存在,是不可缺少的一部分.当然Servlet作为JavaWeb的三大组件之一(其他 ...

  9. 前端性能优化:gzip压缩文件传输数据

    一.文件压缩的好处 前端生产环境中将js.css.图片等文件进行压缩的好处显而易见,通过减少数据传输量减小传输时间,节省服务器网络带宽,提高前端性能. 二.http协议如何支持压缩文件的传输 1.浏览 ...

  10. html2pdf 中文支持问题

    系统用的是HTML2PDF V4.0.3 版本 百度后 http://blog.sina.com.cn/s/blog_6b0ce0310101fdv6.html 发现中文支持不好 还是有乱码问题 解决 ...