Description

Write a method anagram(s,t) to decide if two strings are anagrams or not.

Clarification

What is Anagram?

  • Two strings are anagram if they can be the same after change the order of characters.

Example

Given s = "abcd", t = "dcab", return true.
Given s = "ab", t = "ab", return true.
Given s = "ab", t = "ac", return false.

Challenge

O(n) time, O(1) extra space

解题:题目给定两个字符串,判断这两个字符串除了字符字符顺序不同外,是否相等。最容易想到的还是将字符排序,判断对位字符是否相等。不过在java中,要对字符串中的字符排序,只能转化成字符数组,那么就不满足challenge条件了。但是用其他方法(例如哈希表),代码就只能处理字母或者ASCII中的字符,有损通用性,没什么意思。贴一下排序方法的代码:

 public class Solution {
/**
* @param s: The first string
* @param t: The second string
* @return: true or false
*/
public boolean anagram(String s, String t) {
// write your code here
char[]arr_s = s.toCharArray();
char[]arr_t = t.toCharArray();
Arrays.sort(arr_s);
Arrays.sort(arr_t);
return String.valueOf(arr_s).equals(String.valueOf(arr_t));
}
}

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