PAT (Advanced Level) 1036. Boys vs Girls (25)
简单题。
#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
#include<map>
#include<queue>
#include<vector>
using namespace std; const int maxn=;
struct X
{
string name;
string sex;
string id;
int c;
}s[maxn];
int n; int main()
{
scanf("%d",&n);
for(int i=;i<=n;i++)
cin>>s[i].name>>s[i].sex>>s[i].id>>s[i].c;
int id1=-,id2=-;
int Max=-,Min=;
for(int i=;i<=n;i++)
if(s[i].sex[]=='F'&&s[i].c>Max) Max=s[i].c,id1=i; for(int i=;i<=n;i++)
if(s[i].sex[]=='M'&&s[i].c<Min) Min=s[i].c,id2=i; if(id1==-) printf("Absent\n");
else cout<<s[id1].name<<" "<<s[id1].id<<endl; if(id2==-) printf("Absent\n");
else cout<<s[id2].name<<" "<<s[id2].id<<endl; if(id1==-||id2==-) printf("NA\n");
else printf("%d\n",abs(s[id1].c-s[id2].c)); return ;
}
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