B. Vanya and Books
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Vanya got an important task — he should enumerate books in the library and label each book with its number. Each of the n books should be assigned with a number from 1 to n. Naturally, distinct books should be assigned distinct numbers.
Vanya wants to know how many digits he will have to write down as he labels the books.
InputThe first line contains integer n (1 ≤ n ≤ 109) — the number of books in the library.
OutputPrint the number of digits needed to number all the books.
Examplesinput13output17input4output4NoteNote to the first test. The books get numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, which totals to 17 digits.
Note to the second sample. The books get numbers 1, 2, 3, 4, which totals to 4 digits.
题意:
求从1~n共出现了多少个数字。
附AC代码:
#include<bits/stdc++.h>
using namespace std; int main(){
int n;
cin>>n;
long long ans=,sum=;
while(n-ans>=){
sum+=n-ans+;
ans*=;
}
cout<<sum<<endl;
return ;
}
B. Vanya and Books的更多相关文章
- Codeforces Round #308 (Div. 2)B. Vanya and Books 数学
B. Vanya and Books Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/552/pr ...
- B. Vanya and Books( Codeforces Round #308 (Div. 2) 简单题)
B. Vanya and Books time limit per test 1 second memory limit per test 256 megabytes input standard i ...
- 数学 Codeforces Round #308 (Div. 2) B. Vanya and Books
题目传送门 /* 水题:求总数字个数,开long long竟然莫名其妙WA了几次,也没改啥又对了:) */ #include <cstdio> #include <iostream& ...
- 【33.33%】【codeforces 552B】Vanya and Books
time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...
- #308 (div.2) B. Vanya and Books
1.题目描写叙述:点击打开链接 2.解题思路:本题要求统计数位的个数,简单的试验一下发现有例如以下规律:一个n位数的个数有9*(10^n)个.因此全部n位数的数位是n*9*(10^n)个.因此能够利用 ...
- Codeforces Round #308 (Div. 2) A B C 水 数学
A. Vanya and Table time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Codeforces Round #308 (Div. 2)
A. Vanya and Table Vanya has a table consisting of 100 rows, each row contains 100 cells. The rows ...
- codeforces C. Vanya and Scales
C. Vanya and Scales Vanya has a scales for weighing loads and weights of masses w0, w1, w2, ..., w10 ...
- 7 Must Read Python Books
7 Must Read Python Books I started learning Python just two years ago. Coming from a C++ and Java ba ...
随机推荐
- 【面试 struts2】【第三篇】struts2的问题
1.struts2的工作流程 1>客户端浏览器发出HTTP请求. 2>根据web.xml配置,该请求被FilterDispatcher接收 3>根据struts.xml配置,找到需要 ...
- 【Todo】【读书笔记】Career Cup 150笔记
下载了第五版:/Users/baidu/Documents/Data/Interview/算法与数据结构/<CareerCup+Top+150+Questions+5th.pdf> 参考这 ...
- ElasticSearch集群本机搭建
ElasticSearch集群本机搭建 elasticsearch elasticsearch -Ehttp.port=8200 -Epath.data=node2 elasticsearch -Eh ...
- Ghost本地安装highlight.js使代码高亮
对于程序猿写博客来说,这代码高亮是起码的要求.可是Ghost本身没有支持高亮代码. 可是能够通过扩展来实现,它就是highlight.js--附官方站点,看了下首页介绍,真的非常强大,如今说说怎么进行 ...
- POJ3420 Quad Tiling DP + 矩阵高速幂
题目大意是用1*2的骨牌堆积成4*N的矩形.一共同拥有多少种方法,N不超过10^9. 这题和以前在庞果网上做过的一道木块砌墙差点儿一样. 由于骨牌我们能够横着放.竖着放.我们如果以4为列,N为行这样去 ...
- Android设置系统开机自己主动永不休眠
android4.2系统增永不休眠同一时候隐藏休眠选项 1. android\frameworks\base\packages\SettingsProvider\res\values\defaults ...
- DRP——Dom4j使用
dom4j是一个Java的XMLAPI,类似于jdom.用来读写XML文件的.dom4j是一个很很优秀的JavaXMLAPI.具有性能优异.功能强大和极端易用使用的特点.Dom4j是一个易用的.开源的 ...
- iOS清理WebView的缓存
NSHTTPCookie *cookie; NSHTTPCookieStorage *storage = [NSHTTPCookieStorage sharedHTTPCookieStorage]; ...
- ACM在线题库
现在网上有许多题库,大多是可以在线评测,所以叫做Online Judge.除了USACO是为IOI准备外,其余几乎全部是大学的ACM竞赛题库. USACO http://ace.delos.com/u ...
- java序员必备的十大技能
想成为一名出色的Java程序员么?本文将为大家重点介绍程序员必备的十大技能,成就您的梦想. 1.语法:必须比较熟悉,在写代码的时候IDE的编辑器对某一行报错应该能够根据报错信息知道是什么样 ...