HDU 4749 Parade Show(暴力水果)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4749

2013 is the 60 anniversary of Nanjing University of Science and Technology, and today happens to be the anniversary date. On this happy festival, school authority hopes that the new students to be trained for the parade show. You should plan a better solution
to arrange the students by choosing some queues from them preparing the parade show. (one student only in one queue or not be chosen)
Every student has its own number, from 1 to n. (1<=n<=10^5), and they are standing from 1 to n in the increasing order the same with their number order. According to requirement of school authority, every queue is consisted of exactly m students. Because
students who stand adjacent in training are assigned consecutive number, for better arrangement, you will choose in students with in consecutive numbers. When you choose these m students, you will rearrange their numbers from 1 to m, in the same order with
their initial one.
If we divide our students’ heights into k (1<=k<=25) level, experience says that there will exist an best viewing module, represented by an array a[]. a[i] (1<=i<=m)stands for the student’s height with number i. In fact, inside a queue, for every number pair
i, j (1<=i,j<=m), if the relative bigger or smaller or equal to relationship between the height of student number i and the height of student number j is the same with that between a[i] and a[j], then the queue is well designed. Given n students’ height array
x[] (1<=x[i]<=k), and the best viewing module array a[], how many well designed queues can we make at most?
First line, 3 integers, n (1<=n<=10^5) m (1<=m<=n) k(1<=k<=25),
Second line, n students’ height array x[] (1<=x[i]<=k,1<=i<=n);
Third line, m integers, best viewing module array a[] (1<=a[i]<=k,1<=i<=m);
10 5 10
2 4 2 4 2 4 2 4 2 4
1 2 1 2 1
1
题意:
给出了一列数,再给出了一列參照的数列其每一个数代表一个高度且须满足大小关系。求能够将所给的数列切割成多少个满足參照数列个数和高度的数列!
PS:
数据太水了。暴力过了!
正解貌似是KMP, 算了日后再补正解吧!
代码例如以下:
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <iostream>
using namespace std;
const int maxn = 100017;
int a[maxn], b[maxn]; int main()
{
int n, m, k;
while(~scanf("%d%d%d",&n,&m,&k))
{
for(int i = 0; i < n; i++)
{
scanf("%d",&a[i]);
}
for(int i = 0; i < m; i++)
{
scanf("%d",&b[i]);
}
int cont = 0;
for(int i = 0; i <= n-m; i++)
{
int tt = 0;
for(int j = 0,l = i; l < m+i-1; l++,j++)
{
if((a[l]==a[l+1]&&b[j]==b[j+1]) || (a[l]>a[l+1]&&b[j]>b[j+1]) || (a[l]<a[l+1]&&b[j]<b[j+1]))
{
tt++;
}
else
break;
}
if(tt == m-1)
{
cont++;
i+=m-1;
}
}
printf("%d\n",cont);
}
return 0;
}
HDU 4749 Parade Show(暴力水果)的更多相关文章
- HDU 4749 Parade Show 2013 ACM/ICPC Asia Regional Nanjing Online
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4749 题目大意:给一个原序列N,再给出一个序列M,问从N中一共可以找出多少个长度为m的序列,序列中的数 ...
- HDU 4749 Parade Show(贪心+kmp)
题目链接 题目都看不懂,做毛线...看懂了之后就是kmp出,所有的匹配区间,然后DP可以写,贪心也可以做把,DP应该需要优化一下,直接贪,也应该对的,经典贪心问题. #include<iostr ...
- HDU 4749: Parade Show
看大神代码,发现上交大神很棒的一个思路 题意: 在源数字串中找出尽量多的连续子串,要求子串任意两值的大小关系与目标串相同位置的值的大小关系相同.求源串能拿出的子串的最大数量. 关键词: RK-Hash ...
- hdu 5461 Largest Point 暴力
Largest Point Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid= ...
- hdu 5762 Teacher Bo 暴力
Teacher Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 Description Teacher BoBo is a geogra ...
- HDU 1333 基础数论 暴力
定义一种数位simth数,该数的各位之和等于其所有质因子所有位数字之和,现给出n求大于n的最小该种数,n最大不超过8位,那么直接暴力就可以了. /** @Date : 2017-09-08 14:12 ...
- HDU 4618 Palindrome Sub-Array 暴力
Palindrome Sub-Array 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=4618 Description A palindrome s ...
- HDU 2089 不要62 | 暴力(其实是个DP)
题目: http://acm.hdu.edu.cn/showproblem.php?pid=2089 题解: 暴力水过 #include<cstdio> #include<algor ...
- HDU 6115 Factory LCA,暴力
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6115 题意:中文题面 分析:直接维护LCA,然后暴力枚举集合维护答案即可. #include < ...
随机推荐
- 【jQuery】对于复选框操作的attr与prop
这个是在jQuery1.6版本号之后出现的鬼东西.受影响的主要有下拉列表select与复选框checkbox.众所周知.在jQuery中能够用attr()取出节点的属性,然而对于checkbox却不是 ...
- Java关键字整理之二
abstrac和interface 一.抽象类:abstract 抽象类就是为了继承而存在的,如果你定义了一个抽象类,却不去继承它,那么等于白白创建了这个抽象类,因为你不能用它来做任何事情.对于一个父 ...
- [总结]FFMPEG视音频编解码零基础学习方法【转】
本文转载自:http://blog.csdn.net/leixiaohua1020/article/details/15811977 在CSDN上的这一段日子,接触到了很多同行业的人,尤其是使用FFM ...
- Swift-UITextField用法
文本框的创建,如下几种方式: UITextBorderStyle.None:无边框 UITextBorderStyle.Line:直线边框 UITextBorderStyle.RoundedRect: ...
- maven冲突管理及依赖管理实践
1.“最近获胜策略(nearest wins strategy)”的方式处理依赖冲突 Maven采用“最近获胜策略(nearest wins strategy)”的方式处理依赖冲突,即如果一个项目最终 ...
- linux + nginx 的配置优化
linux 关于TCP/IP 的优化配置 配置文件/etc/sysctl.conf 修改完文件生效的命令 /sbin/sysctl -p 如下是总结的配置内容及说明 net.ipv4.con ...
- tp5数据库操作 Db类
一.链接数据库 1.配置文件定义 application\database.php 注意:数据表前缀更改,在文件的prefix选项 2.类定义 二.数据库的基本使用 namespace app\de ...
- LeetCode224. Basic Calculator (用栈计算表达式)
解题思路 用两个栈分别存字符和数字. 顺序读入字符,处理方式分为字符和数字两种. 处理字符分为')'和非')'两种. 处理数字需要读取字符栈栈顶,分为'+'.'-'和非'+'.'-'. 代码 clas ...
- VC工程里,如何编译汇编语言的文件
最近老是有朋友问,VC工程里,如何编译汇编语言的文件,接下来就说一下步骤: 1.将汇编语言文件,加入到工程里: 2.在Solution Explorer窗口中右键单击Visual C++项目,选择Bu ...
- 让html页面不缓存js的实现方法
很多朋友都会碰到这样的情况:如果我们页面加载了js的话下次打开时也会是调用这个js缓存文件,但对于我们调试时是非常的不方便了,本文就来谈论如何解决这一问题,下面一起来看看. 不缓存JS的方法其实挺简单 ...