引用:https://blog.csdn.net/qq_41879343/article/details/100565031

下面代码写错了,注意要上面这种。查:2  800  0,下面代码就错了。

 #define IOS ios_base::sync_with_stdio(0); cin.tie(0);
#include <cstdio>//sprintf islower isupper
#include <cstdlib>//malloc exit strcat itoa system("cls")
#include <iostream>//pair
#include <fstream>//freopen("C:\\Users\\13606\\Desktop\\草稿.txt","r",stdin);
#include <bitset>
//#include <map>
//#include<unordered_map>
#include <vector>
#include <stack>
#include <set>
#include <string.h>//strstr substr
#include <string>
#include <time.h>//srand(((unsigned)time(NULL))); Seed n=rand()%10 - 0~9;
#include <cmath>
#include <deque>
#include <queue>//priority_queue<int, vector<int>, greater<int> > q;//less
#include <vector>//emplace_back
//#include <math.h>
//#include <windows.h>//reverse(a,a+len);// ~ ! ~ ! floor
#include <algorithm>//sort + unique : sz=unique(b+1,b+n+1)-(b+1);+nth_element(first, nth, last, compare)
using namespace std;//next_permutation(a+1,a+1+n);//prev_permutation
#define fo(a,b,c) for(register int a=b;a<=c;++a)
#define fr(a,b,c) for(register int a=b;a>=c;--a)
#define mem(a,b) memset(a,b,sizeof(a))
#define pr printf
#define sc scanf
#define ls rt<<1
#define rs rt<<1|1
typedef long long ll;
void swapp(int &a,int &b);
double fabss(double a);
int maxx(int a,int b);
int minn(int a,int b);
int Del_bit_1(int n);
int lowbit(int n);
int abss(int a);
//const long long INF=(1LL<<60);
const double E=2.718281828;
const double PI=acos(-1.0);
const int inf=(<<);
const double ESP=1e-;
const int mod=(int)1e9+;
const int N=(int)1e6+; ll a[N];
ll ans[][]; int main()
{
int n;
sc("%d",&n);
fo(n_,,n)
{
int judge,x,y;
sc("%d%d%d",&judge,&x,&y);
if(judge==)
{
a[x]+=y;
for(int i=;i<=;++i)
ans[x%i][i]+=y;
}
else
{
ll Ans=;
if(x<=)
Ans+=ans[y][x];
else
for(int i=;i<=;i+=x)
Ans+=a[i+y-];
pr("%lld\n",Ans);
}
}
return ;
} /**************************************************************************************/ int maxx(int a,int b)
{
return a>b?a:b;
} void swapp(int &a,int &b)
{
a^=b^=a^=b;
} int lowbit(int n)
{
return n&(-n);
} int Del_bit_1(int n)
{
return n&(n-);
} int abss(int a)
{
return a>?a:-a;
} double fabss(double a)
{
return a>?a:-a;
} int minn(int a,int b)
{
return a<b?a:b;
}

Remainder Problem(分块) Educational Codeforces Round 71 (Rated for Div. 2)的更多相关文章

  1. Educational Codeforces Round 71 (Rated for Div. 2)-F. Remainder Problem-技巧分块

    Educational Codeforces Round 71 (Rated for Div. 2)-F. Remainder Problem-技巧分块 [Problem Description] ​ ...

  2. Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题

    Educational Codeforces Round 71 (Rated for Div. 2)-E. XOR Guessing-交互题 [Problem Description] ​ 总共两次询 ...

  3. Educational Codeforces Round 71 (Rated for Div. 2)

    传送门 A.There Are Two Types Of Burgers 签到. B.Square Filling 签到 C.Gas Pipeline 每个位置只有"高.低"两种状 ...

  4. Educational Codeforces Round 71 (Rated for Div. 2) Solution

    A. There Are Two Types Of Burgers 题意: 给一些面包,鸡肉,牛肉,你可以做成鸡肉汉堡或者牛肉汉堡并卖掉 一个鸡肉汉堡需要两个面包和一个鸡肉,牛肉汉堡需要两个面包和一个 ...

  5. Educational Codeforces Round 71 (Rated for Div. 2)E. XOR Guessing

    一道容斥题 如果直接做就是找到所有出现过递减的不同排列,当时硬钢到自闭,然后在凯妹毁人不倦的教导下想到可以容斥做,就是:所有的排列设为a,只考虑第一个非递减设为b,第二个非递减设为c+两个都非递减的情 ...

  6. Educational Codeforces Round 71 (Rated for Div. 2) E XOR Guessing (二进制分组,交互)

    E. XOR Guessing time limit per test1 second memory limit per test256 megabytes inputstandard input o ...

  7. [暴力] Educational Codeforces Round 71 (Rated for Div. 2) B. Square Filling (1207B)

    题目:http://codeforces.com/contest/1207/problem/B   B. Square Filling time limit per test 1 second mem ...

  8. [贪心,dp] Educational Codeforces Round 71 (Rated for Div. 2) C. Gas Pipeline (1207C)

    题目:http://codeforces.com/contest/1207/problem/C   C. Gas Pipeline time limit per test 2 seconds memo ...

  9. XOR Guessing(交互题+思维)Educational Codeforces Round 71 (Rated for Div. 2)

    题意:https://codeforc.es/contest/1207/problem/E 答案guessing(0~2^14-1) 有两次机会,内次必须输出不同的100个数,每次系统会随机挑一个你给 ...

随机推荐

  1. c++学习之单链表以及常用的操作

    新学数据结构,上我写的代码. #include <iostream> #include <cstdlib> using namespace std; typedef int E ...

  2. 【零基础】入门51单片机图文教程(Proteus+Keil)

    参考资料: https://www.jianshu.com/p/88dfc09e7403 https://blog.csdn.net/feit2417/article/details/80890218 ...

  3. python编码,三个编码实例

    1.字符串编码设置 data = u'你好' utf8 = data.encode('utf-8') 2.管道编码设置 import locale import sys ###设置输出管道编码### ...

  4. 阿里云Ubuntu 16 FTP安装配置注意事项

    1. 开放端口设置 阿里云控制台添加"安全组规则". 1) 21: FTP端口; 2) 15000~15100: 对应vsftpd.conf 自定义配置. (重要!) pasv_e ...

  5. Android Studio NDK编程-环境搭建及Hello!

    一,下载 安装android-ndk开发包 NDK各个版本链接二,新建项目NDKDemo,选择空Activity就可以:(注:Android studio 2.2,可通过SDK Tools 添加LLD ...

  6. redis的服务器信息状态信息查看

    Redis的服务器信息状态信息查看 Redis的提供了一个信息命令查看Redis的服务器的信息,类似的Linux提供一个顶级命令查看系统的信息 redis-cli info # Server #服务器 ...

  7. React Native中Navigator的安装与使用

    一.安装Navigator 1.安装react-native-deprecated-custom-components npm install react-native-deprecated-cust ...

  8. TP5连接数据库和phpstrom连接数据库(宝塔面板数据库连接)

    1.编译器:phpstrom 框架:TP5 服务器面板:宝塔面板 2.我遇到的核心问题:数据库.用户名.密码均正确但是无法连接, 使用宝塔面板的都知道phpmyadmin的端口号是888,注意注意这个 ...

  9. 2018网特招新题writeup

    沈永宁(周鸣振)这狗比,晚上才发现他隐姓埋名偷偷刷了分还刷到了第一名,不行我也刷...我刷刷刷

  10. Linux (Ubuntu)安装nexus,搭建maven私有服务器

     下载 nexus oos(开源版)https://www.sonatype.com/download-oss-sonatype 2 将下载的压缩包上传到/opt/nexus/文件夹下面 3 解压文件 ...