Java实现 LeetCode 478 在圆内随机生成点
478. 在圆内随机生成点
给定圆的半径和圆心的 x、y 坐标,写一个在圆中产生均匀随机点的函数 randPoint 。
说明:
输入值和输出值都将是浮点数。
圆的半径和圆心的 x、y 坐标将作为参数传递给类的构造函数。
圆周上的点也认为是在圆中。
randPoint 返回一个包含随机点的x坐标和y坐标的大小为2的数组。
示例 1:
输入:
[“Solution”,“randPoint”,“randPoint”,“randPoint”]
[[1,0,0],[],[],[]]
输出: [null,[-0.72939,-0.65505],[-0.78502,-0.28626],[-0.83119,-0.19803]]
示例 2:
输入:
[“Solution”,“randPoint”,“randPoint”,“randPoint”]
[[10,5,-7.5],[],[],[]]
输出: [null,[11.52438,-8.33273],[2.46992,-16.21705],[11.13430,-12.42337]]
输入语法说明:
输入是两个列表:调用成员函数名和调用的参数。Solution 的构造函数有三个参数,圆的半径、圆心的 x 坐标、圆心的 y 坐标。randPoint 没有参数。输入参数是一个列表,即使参数为空,也会输入一个 [] 空列表。
class Solution {
private double radius;
private double x_center;
private double y_center;
public Solution(double radius, double x_center, double y_center) {
this.radius = radius;
this.x_center = x_center;
this.y_center = y_center;
}
public double[] randPoint() {
Random random = new Random();
double x = x_center-radius + 2*radius*random.nextDouble();
double y = y_center-radius + 2*radius*random.nextDouble();
while(Math.sqrt(Math.pow(x - x_center, 2) + Math.pow(y - y_center, 2)) > radius){
x = x_center-radius + 2*radius*random.nextDouble();
y = y_center-radius + 2*radius*random.nextDouble();
}
return new double[]{x, y};
}
}
/**
* Your Solution object will be instantiated and called as such:
* Solution obj = new Solution(radius, x_center, y_center);
* double[] param_1 = obj.randPoint();
*/
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