HDU-1036 Average is not Fast Enough!

Average is not Fast Enough!

http://acm.hdu.edu.cn/showproblem.php?pid=1036

Problem Description

A relay is a race for two or more teams of runners. Each member of a team runs one section of the race. Your task is to help to evaluate the results of a relay race.

You have to process several teams.
For each team you are given a list with the running times for every section of
the race. You are to compute the average time per kilometer over the whole
distance. That's easy, isn't it?
So if you like the fun and challenge
competing at this contest, perhaps you like a relay race, too. Students from Ulm
participated e.g. at the "SOLA" relay in Zurich, Switzerland. For more
information visit http://www.sola.asvz.ethz.ch/ after the contest is
over.

 

Input

The first line of the input specifies the number of
sections n followed by the total distance of the relay d in kilometers. You may
safely assume that 1 <= n <= 20 and 0.0 < d < 200.0. Every following
line gives information about one team: the team number t (an integer,
right-justified in a field of width 3) is followed by the n results for each
section, separated by a single space. These running times are given in the
format "h:mm:ss" with integer numbers for the hours, minutes and seconds,
respectively. In the special case of a runner being disqualified, the running
time will be denoted by "-:--:--". Finally, the data on every line is terminated
by a newline character. Input is terminated by EOF.

 

Output

For each team output exactly one line giving the team's
number t right aligned in a field of width 3, and the average time for this team
rounded to whole seconds in the format "m:ss". If at least one of the team's
runners has been disqualified, output "-" instead. Adhere to the sample output
for the exact format of presentation.

 

Sample Input

2 12.5
5 0:23:21 0:25:01
42 0:23:32 -:--:--
7 0:33:20 0:41:35

 

Sample Output

5: 3:52 min/km
42: -
7: 6:00 min/km

 

#include<stdio.h>
int main()
{
    int n;
    double d;
    int num;
    char h,m1,m2,s1,s2;
    scanf("%d",&n);
    scanf("%lf",&d);
    while(scanf("%d",&num)!=EOF)
    {

        printf("%3d: ",num);
        bool flag=true;
        int sumtime=;
        for(int i=;i<n;i++)
        {getchar();
            scanf("%c:%c%c:%c%c",&h,&m1,&m2,&s1,&s2);
            if(h=='-') flag=false;
            if(flag==false)continue;
            sumtime+=(h-'')*+((m1-'')*+(m2-''))*+(s1-'')*+(s2-'');
        }
        if(flag==false)printf("-\n");
        else
        {
            double t1=sumtime/d;
            int t2=(int)(t1+0.5);
            printf("%d:%02d min/km\n",t2/,t2%);

        }
    }
    return ;
}