Problem Description

Given an positive integer A (1 <= A <= 100), output the lowest bit of A.



For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2.



Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.





Input

Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.





Output

For each A in the input, output a line containing only its lowest bit.





Sample Input

26

88

0





Sample Output

2

8

啥也不说了!!!水题!!!!

代码:

#include <iostream>
#include <string>
#include <stdio.h>
#include <algorithm>
#include <cmath>
#include <cstring>
#include <iomanip> using namespace std;
int lowbit(int x)
{
return x&(-x);
}
int main()
{ int n;
while(cin>>n&&n)
{
cout<<lowbit(n)<<endl;
}
return 0;
}

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