深度优先非递归实现算法:

1 递归算法:

//初始化相关数据结构
DFS(G)
-----------------------------------------------------------------------------------
1 for each vertex u ∈ G.V
2 u.color ← WHITE // paint all vertices white; undiscovered
3 u.π ← NIL
4 time ← 0 // global variable, timestamps
5 for each vertex u ∈ G.V
6 if u.color = WHITE
7 DFS-VISIT(G,u) DFS-VISIT(G, u)
-----------------------------------------------------------------------------------
1 u.color ← GRAY // grey u; it is discovered
2 time ← time + 1
3 u.d ← time
4 for each v ∈ G.Adj[u] // explore edge (u,v)
5 if v.color == WHITE
6 v.π ← u
7 DFS-VISIT(G,v)
8 u.color ← BLACK // blacken u; it is finished
9 time ← time + 1
10 u.f ← time

#ifndef GCC_LINUX_
#include <stdlib.h>
#include <iostream>
using namespace std;
#endif
#include "Graph.h" enum color{WHITE, GRAY, BLACK};
int colour[MAX_VERTEX_NUM];
int time[MAX_VERTEX_NUM];
int curTime; void DFSRec(LGraph graph, int u){
cout<<"for debug"<<endl;
cout<<"u: "<<u<<endl;
colour[u] = GRAY;
time[u] = ++curTime;
//DFS adj node
adjnode *temp;
temp = graph.vertices[u].firstadj; while(temp){
int v = temp->index;
//for debug
cout<<"for debug"<<endl;
cout<<"v: "<<v<<" line: "<<__LINE__<<endl;
if(colour[v] == WHITE)
DFSRec(graph, v);
else if(colour[v] == GRAY)
cout<<"back edge between "<<u<<" and "<<v<<endl;
else
cout<<"cross edge between "<<u<<" and "<<v<<endl;
temp = temp->adjnext;
}
colour[u] = BLACK;
} void DFSTraverse(LGraph graph){
for(int k = 1; k < graph.vexnum + 1; k++){
if(colour[k] == WHITE) DFSRec(graph, k);
cout<<__LINE__<<" for debug: "<<k<<endl;
}
} int main()
{
LGraph* graph;
graph = CreateGraph(graph);
cout<<graph->edgenum<<endl;
cout<<graph->vexnum<<endl;
print(*graph);
DFSTraverse(*graph);
//print time visit
cout<<"print the visit array:"<<endl;
for(int i = 1; i < graph->vexnum + 1; i++)
cout<<time[i]<<" ";
cout<<endl; int ch;
cout<<"enter integer for terminating:"<<endl;
cin>>ch;
return 0;
}

2 非递归算法

1   for each vertex u ∈ G.V //initialize colour array and time
2 u.color ← WHITE
3 u.π ← NIL
4 time = 0
5 for each vertex u ∈ G.V
6 if u.color = WHITE
7 u.color ← GRAY
8 time ← time + 1
9 u.d ← time
7 push(u, S)
8 while stack S not empty
9 u ← pop(S)
10 for each vertex v ∈ G.Adj[u]
11 if v.color = WHITE
12 v.color = GRAY
13 time ← time + 1
14 v.d ← time
15 v.π ← u
16 push(v, S)
17 u.color ← BLACK
18 time ← time + 1
19 u.f ← time
具体实现代码如下:
栈采用数组实现:
#ifndef GCC_LINUX_
#include <stdlib.h>
#include <iostream>
using namespace std;
#endif
#include "Graph.h" int myStack[MAX_VERTEX_NUM];
int top = 0; //we not use array[0]
bool visited[MAX_VERTEX_NUM];
int timeSec[MAX_VERTEX_NUM];
int curTimeSec; void DFSNoRecur(LGraph graph, int u){
cout<<u;
myStack[top++] = u;
cout<<" top:"<<top<<endl;
adjnode* temp;
//for test
int test = 1;
while(top){
int v = myStack[top - 1];
cout<<test++<<" for test top: "<<top;
cout<<" stack elem: "<<v<<endl;
visited[v] = true;
timeSec[v] = ++curTimeSec;
temp = graph.vertices[v].firstadj;
cout<<"pointer temp: "<<temp<<endl;
top--; //Pop
cout<<top;
while(temp != NULL){
if(visited[temp->index] == false){
myStack[top++] = temp->index;
cout<<test++<<" for test top: "<<top;
cout<<" stack elem: "<<myStack[top - 1]<<endl;
}
else{
cout<<"back edge between "<<temp->index;
cout<<" and "<<v<<endl;
}
temp = temp->adjnext;
}//while
}//while(top)
} void DFSTravNRecur(LGraph graph){
cout<<"No recursive DFS starting"<<endl;
for(int v = 1; v < graph.vexnum + 1; v++)
if(visited[v] == false) DFSNoRecur(graph, v);
cout<<"No recursive DFS terminating"<<endl;
} int main()
{
LGraph* graph;
graph = CreateGraph(graph);
cout<<graph->edgenum<<endl;
cout<<graph->vexnum<<endl;
print(*graph);
DFSTraverse(*graph);
//print time visit
cout<<"print the time array:"<<endl;
for(int i = 1; i < graph->vexnum + 1; i++)
cout<<time[i]<<" ";
cout<<endl; DFSTravNRecur(*graph);
cout<<"print the visit array:"<<endl;
for(int i = 1; i < graph->vexnum + 1; i++)
cout<<time[i]<<" ";
cout<<endl; int ch;
cout<<"enter integer for terminating:"<<endl;
cin>>ch;
return 0;
}

"Graph.h"文件代码定义:

#ifndef GCC_LINUX_
#include <stdlib.h>
#include <iostream>
using namespace std;
#endif
#define MAX_VERTEX_NUM 128 struct adjnode{
int index;
struct adjnode* adjnext;
}; typedef struct vexnode{
struct adjnode* firstadj;
}VertexLink[MAX_VERTEX_NUM]; typedef struct LGraph{
VertexLink vertices;
int vexnum, edgenum; }; void AddEdge(LGraph *graph, int head, int tail){
//new a adj node
adjnode *newadjnode = (adjnode*)malloc(sizeof(struct adjnode));
if(!newadjnode)
exit(EXIT_FAILURE);
newadjnode->index = tail;
newadjnode->adjnext = NULL;
adjnode *temp; temp = graph->vertices[head].firstadj;
cout<<"this edge: "<<head<<"->"<<newadjnode->index<<endl;
newadjnode->adjnext =temp;
graph->vertices[head].firstadj = newadjnode;
//debug
cout<<"line: "<<__LINE__;
cout<<" first adj index: "<<graph->vertices[head].firstadj->index<<endl; } LGraph* CreateGraph(LGraph *graph){
graph = (LGraph*)malloc(sizeof(struct LGraph));
if(!graph)
exit(EXIT_FAILURE);
cout<<"enter the vertex number and edge number:"<<endl;
cin>>graph->vexnum>>graph->edgenum; //initialize the vertexes
for(int v = 0; v < graph->vexnum + 1; v++){
graph->vertices[v].firstadj = NULL;
} //initialize the edge
int i, j;
for(int e = 0; e < graph->edgenum; e++){
cout<<"enter edge of graph:"<<endl;
cin>>i>>j;
AddEdge(graph, i, j);
}
cout<<"graph.vertex number: "<<graph->vexnum<<endl;
return graph;
} void print(LGraph graph){
adjnode *temp = NULL;
for(int i = 1; i < graph.vexnum + 1; i++){
cout<<"vertex: "<<i;
temp = graph.vertices[i].firstadj;
// cout<<"temp"<<temp<<endl;
while(temp){
cout<<" adj vertex: "<<temp->index<<endl;
temp = temp->adjnext;
}
}
cout<<endl;
}

版权声明:本文为博主原创文章,未经博主允许不得转载。

Non recursive Depth first search的更多相关文章

  1. Recursive Depth first search graph(adj matrix)

    1 深度优先遍历邻接矩阵 1 邻接矩阵初始化 2 访问数组初始化 3 深度优先遍历邻接矩阵图 算法如下: bool MGraph[128][128]; bool visit[128]; int vex ...

  2. [算法&数据结构]深度优先搜索(Depth First Search)

    深度优先 搜索(DFS, Depth First Search) 从一个顶点v出发,首先将v标记为已遍历的顶点,然后选择一个邻接于v的尚未遍历的顶点u,如果u不存在,本次搜素终止.如果u存在,那么从u ...

  3. [Algorithm] Write a Depth First Search Algorithm for Graphs in JavaScript

    Depth first search is a graph search algorithm that starts at one node and uses recursion to travel ...

  4. 幸运的袋子(深度优先遍历(Depth First Search,DFS))

    题目描述 一个袋子里面有n个球,每个球上面都有一个号码(拥有相同号码的球是无区别的).如果一个袋子是幸运的当且仅当所有球的号码的和大于所有球的号码的积. 例如:如果袋子里面的球的号码是{1, 1, 2 ...

  5. 深度优先搜索(Depth First Search)

    Date:2019-07-01 15:31:11 通俗点理解就是不撞南墙不回头的那种,用栈来实现 算法实现 /* 题目描述: 有n件物品,每件物品的重量为w[i],价值为c[i].现在需要选出若干件物 ...

  6. Add Digits, Maximum Depth of BinaryTree, Search for a Range, Single Number,Find the Difference

    最近做的题记录下. 258. Add Digits Given a non-negative integer num, repeatedly add all its digits until the ...

  7. [数据结构]——二叉树(Binary Tree)、二叉搜索树(Binary Search Tree)及其衍生算法

    二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现 ...

  8. [LeetCode] Maximum Depth of Binary Tree 二叉树的最大深度

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

  9. [LeetCode] 104. Maximum Depth of Binary Tree 二叉树的最大深度

    Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the long ...

随机推荐

  1. mysqldump 利用rr隔离实现一致性备份

    mysqldump -p -S /data/mysqldata1/sock/mysql.sock --single-transaction --master-data=2 --database db1 ...

  2. Java实现HTML转PDF的总结

    Java实现HTML转PDF的几种方法—主要解决中文乱码问题 第一:同事在做HTML转PDF中遇到乱码问题 ********************************************** ...

  3. 命令行方式运行yii2程序

    测试环境,yii 2.0.3版本 web访问方式,控制器放在controllers目录下 ,浏览器访问如下地址 http://127.0.0.1/index.php?r=[controller-nam ...

  4. 纯JavaScript实现HTML5 Canvas六种特效滤镜

    纯JavaScript实现HTML5 Canvas六种特效滤镜  小试牛刀,实现了六款简单常见HTML5 Canvas特效滤镜,并且封装成一个纯 JavaScript可调用的API文件gloomyfi ...

  5. html网页编码问题

    之前碰到过一些html编码乱码问题,都理解的模模糊糊,问了别人解释的也是模模糊糊.近期要做前端这个问题研究了下仅仅须要两句话就能非常清楚的解释了(之前问的那些人是不是自己都没理解非常郁闷.) < ...

  6. 关于css的默认宽度

    <div class="boxa"> <div class="boxb">我是div</div> </div> ...

  7. 通过配置Tomcat,让Android真机通过局域网访问PC的文件

    在 Tomcat 根目录,找到conf\server.xml文件. 1.打开server.xml查找修改端口为8080端口: <Connector port="8080" p ...

  8. 我的iOS学习之路(四):动画设置

    在ios的开发过程中,经常需要对视图控件进行变化,如大小,颜色,旋转等,这是如果直接将变化结果呈现出来,就显得不够友好,所以我们通常会使用动画,让用户能够看到变化的过程. 使用动画通常有两种方式,一种 ...

  9. BZOJ 3931: [CQOI2015]网络吞吐量( 最短路 + 最大流 )

    最短路 + 最大流 , 没什么好说的... 因为long long WA 了两次.... ------------------------------------------------------- ...

  10. ie浏览器css中的行为expression详解

    CSS中的行为——expression (ie only) 最近对CSS中的行为比较感兴趣,虽然是不符合标准的也只有ie才能识别,但是他确实给css的功能扩展了不少.下面是摘自互联网上的文字和例子,因 ...