Problem Description
ZYB played a game named NumberBomb with his classmates in hiking:a host keeps a number in [,N] in mind,then
players guess a number in turns,the player who exactly guesses X loses,or the host will tell all the players that
the number now is bigger or smaller than X.After that,the range players can guess will decrease.The range is [,N] at first,each player should guess in the legal range. Now if only two players are play the game,and both of two players know the X,if two persons all use the best strategy,and the first player guesses first.You are asked to find the number of X that the second player
will win when X is in [,N].
Input
In the first line there is the number of testcases T.

For each teatcase:

the first line there is one number N.

≤T≤,≤N≤
 
Output
For each testcase,print the ans.
 
Sample Input

 
Sample Output

 
Source
 #pragma comment(linker, "/STACK:1024000000,1024000000")
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<math.h>
#include<algorithm>
#include<queue>
#include<set>
#include<bitset>
#include<map>
#include<vector>
#include<stdlib.h>
#include <stack>
using namespace std;
#define PI acos(-1.0)
#define max(a,b) (a) > (b) ? (a) : (b)
#define min(a,b) (a) < (b) ? (a) : (b)
#define ll long long
#define eps 1e-10
#define MOD 1000000007
#define N 1000000
#define inf 1e12
int n;
int main()
{
int t;
scanf("%d",&t);
while(t--){
scanf("%d",&n);
if(n%==){
printf("1\n");
}else{
printf("0\n");
} }
return ;
}

hdu 5591 ZYB's Game的更多相关文章

  1. hdu 5591 ZYB's Game 博弈论

    ZYB's Game Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=55 ...

  2. HDU - 5591 ZYB's Game(博弈)

    题意:A和B两人在1~N中选数字.已知1<=X<=N,谁先选中X谁就输.每当一个人选出一个不是X的数,裁判都会说明这个数比X大还是小,与此同时,可选范围随之缩小.已知A先选,求满足能让B赢 ...

  3. hdu 5594 ZYB's Prime 最大流

    ZYB's Prime Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5 ...

  4. hdu 5592 ZYB's Game 树状数组

    ZYB's Game Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=55 ...

  5. HDU 5590 ZYB's Biology 水题

    ZYB's Biology Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid ...

  6. hdu 5268 ZYB loves Score 水题

    ZYB loves Score Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?p ...

  7. HDU 6468 zyb的面试

    http://acm.hdu.edu.cn/showproblem.php?pid=6468 题目 今天zyb参加一场面试,面试官听说zyb是ACMer之后立马抛出了一道算法题给zyb:有一个序列,是 ...

  8. Bestcoder round #65 && hdu 5593 ZYB's Tree 树形dp

    Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submissio ...

  9. Bestcoder round #65 && hdu 5592 ZYB's Premutation 线段树

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submissio ...

随机推荐

  1. JSON.parse()和JSON.stringify()的用法

    JSON.parse()是用于从一个字符串中解析出json对象,如下所示 var str = '{"name":"flsummer","age&quo ...

  2. U盘开发之SSD对比

    U盘因其小巧方便,逐步取代了笨重的移动硬盘和光驱,成为最普及的存储介质.现在的主板BIOS也将支持USB启动,作为标准之一,再过几年,光驱时代可能就要终结了.从早期的16MU盘,到现在动辄几个G,U盘 ...

  3. USB device & USB controller & USB passthrough

    目录 USB device USB controller Linux 相关命令 Python 相关库 Libvirt USB passthrough 参考资料 近期往 openstack 里倒腾 US ...

  4. linux之SQL语句简明教程---外部连接

    之前我们看到的左连接 (left join),又称内部连接 (inner join).在这个情况下,要两个表格内都有同样的值,那一笔资料才会被选出.那如果我们想要列出一个表格中每一笔的资料,无论它的值 ...

  5. poj1581

    A Contesting Decision Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 2519   Accepted: ...

  6. Longest Substring Without Repeating Characters 最长不重复子串

    只遍历一次字符串即可求出最长不重复子串的长度. int lengthOfLongestSubstring(string s) { vector<,-); //记录字符上一次出现的位置,ASCII ...

  7. php排序算法之选择排序

    /** * 选择排序 * 不稳定排序 *工作原理: 首先在未排序序列中找到最小(大)元素,存放到排序序列的起始位置,然后,再从剩余未排序元素中继续寻找最小(大)元素,然后放到已排序序列的末尾.以此类推 ...

  8. ZCTF-final-restaurant1

    和线上赛的题目差别不大,但是需要自己去泄露堆的地址.除了线上赛的溢出之外,还多了一个Use After Free的洞.我写了两种利用方法. 线上赛writeup见:http://www.cnblogs ...

  9. C# 几种退出程序的方式

    C# WinForm程序退出的方法 1.this.Close(); 只是关闭当前窗口,若不是主窗体的话,是无法退出程序的,另外若有托管线程(非主线程),也无法干净地退出: 2.Application. ...

  10. Gradle中文乱码

    代码中的中文注释可能会引起Gradle报错 解决办法: 在项目下的build.gradle下添加以下代码即可解决 [java] view plaincopyprint? tasks.withType( ...