Help Me with the Game
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 3510   Accepted: 2251

Description

Your task is to read a picture of a chessboard position and print it in the chess notation.

Input

The input consists of an ASCII-art picture of a chessboard with chess pieces on positions described by the input. The pieces of the white player are shown in upper-case letters, while the black player's pieces are lower-case letters. The letters are one of "K" (King), "Q" (Queen), "R" (Rook), "B" (Bishop), "N" (Knight), or "P" (Pawn). The chessboard outline is made of plus ("+"), minus ("-"), and pipe ("|") characters. The black fields are filled with colons (":"), white fields with dots (".").

Output

The output consists of two lines. The first line consists of the string "White: ", followed by the description of positions of the pieces of the white player. The second line consists of the string "Black: ", followed by the description of positions of the pieces of the black player.

The description of the position of the pieces is a comma-separated list of terms describing the pieces of the appropriate player. The description of a piece consists of a single upper-case letter that denotes the type of the piece (except for pawns, for that this identifier is omitted). This letter is immediatelly followed by the position of the piece in the standard chess notation -- a lower-case letter between "a" and "h" that determines the column ("a" is the leftmost column in the input) and a single digit between 1 and 8 that determines the row (8 is the first row in the input).

The pieces in the description must appear in the following order: King("K"), Queens ("Q"), Rooks ("R"), Bishops ("B"), Knights ("N"), and pawns. Note that the numbers of pieces may differ from the initial position because of capturing the pieces and the promotions of pawns. In case two pieces of the same type appear in the input, the piece with the smaller row number must be described before the other one if the pieces are white, and the one with the larger row number must be described first if the pieces are black. If two pieces of the same type appear in the same row, the one with the smaller column letter must appear first.

Sample Input

+---+---+---+---+---+---+---+---+
|.r.|:::|.b.|:q:|.k.|:::|.n.|:r:|
+---+---+---+---+---+---+---+---+
|:p:|.p.|:p:|.p.|:p:|.p.|:::|.p.|
+---+---+---+---+---+---+---+---+
|...|:::|.n.|:::|...|:::|...|:p:|
+---+---+---+---+---+---+---+---+
|:::|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|...|:::|...|:::|.P.|:::|...|:::|
+---+---+---+---+---+---+---+---+
|:P:|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|.P.|:::|.P.|:P:|...|:P:|.P.|:P:|
+---+---+---+---+---+---+---+---+
|:R:|.N.|:B:|.Q.|:K:|.B.|:::|.R.|
+---+---+---+---+---+---+---+---+

Sample Output

White: Ke1,Qd1,Ra1,Rh1,Bc1,Bf1,Nb1,a2,c2,d2,f2,g2,h2,a3,e4
Black: Ke8,Qd8,Ra8,Rh8,Bc8,Ng8,Nc6,a7,b7,c7,d7,e7,f7,h7,h6
题目里的升兵为王果然没用
#include<cstdio>
#include <cstring>
#include <cctype>
using namespace std;
char maz[17][34];
char seq[2][6]={{'K','Q','R','B','N','P'},{'k','q','r','b','n','p'}};
bool first;
void subinsrt(int x,int y,char &ch){
ch=maz[2*x+1][4*y+2];
}
void scanner(char ch,bool fl){
char fnd;
if(fl)for(int i=0;i<8;i++){
for(int j=0;j<8;j++){
subinsrt(i,j,fnd);
if(ch==fnd){
if(first){
putchar(',');
}
else first=true;
if(ch!='P'&&ch!='p')putchar(toupper(ch));
printf("%c%d",j+'a',i+1);
}
}
}
else for(int i=7;i>=0;i--){
for(int j=0;j<8;j++){
subinsrt(i,j,fnd);
if(ch==fnd){
if(first){
putchar(',');
}
else first=true;
if(ch!='P'&&ch!='p')putchar(toupper(ch));
printf("%c%d",j+'a',i+1);
}
}
}
}
int main(){
for(int i=16;i>=0;i--)scanf("%s",maz[i]);
first=false;
printf("White: ");
for(int i=0;i<6;i++)scanner(seq[0][i],true);
puts("");
first=false;
printf("Black: ");
for(int i=0;i<6;i++)scanner(seq[1][i],false);
puts("");
return 0;
}

  

快速切题 poj 2996 Help Me with the Game 棋盘 模拟 暴力 难度:0的更多相关文章

  1. 快速切题 poj 2993 Emag eht htiw Em Pleh 模拟 难度:0

    Emag eht htiw Em Pleh Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2806   Accepted:  ...

  2. 快速切题 poj 1003 hangover 数学观察 难度:0

    Hangover Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 103896   Accepted: 50542 Descr ...

  3. 快速切题 poj 1002 487-3279 按规则处理 模拟 难度:0

    487-3279 Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 247781   Accepted: 44015 Descr ...

  4. 快速切题 poj 3026 Borg Maze 最小生成树+bfs prim算法 难度:0

    Borg Maze Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8905   Accepted: 2969 Descrip ...

  5. 快速切题 poj 2485 Highways prim算法+堆 不完全优化 难度:0

    Highways Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 23033   Accepted: 10612 Descri ...

  6. POJ 1321 棋盘问题 dfs 难度:0

    http://poj.org/problem?id=1321 注意是在'#'的地方放棋子 矩阵大小不过8*8,即使是8!的时间复杂度也足以承受,可以直接dfs求解 dfs时标注当前点的行和列已被访问, ...

  7. POJ 3522 Slim Span 最小生成树,暴力 难度:0

    kruskal思想,排序后暴力枚举从任意边开始能够组成的最小生成树 #include <cstdio> #include <algorithm> using namespace ...

  8. poj 2739 Sum of Consecutive Prime Numbers 素数 读题 难度:0

    Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 19697 ...

  9. poj 1258 Agri-Net 最小生成树 prim算法+heap不完全优化 难度:0

    Agri-Net Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 41230   Accepted: 16810 Descri ...

随机推荐

  1. 洛谷P2024 食物链 [NOI2001] 并查集

    正解:并查集 解题报告: 传送门(咕了! 其实没有很难(虽然我是交了三发才过的QAQ 但是一来好久没打并查集了恢复一下智力 二来看着智推里唯一一个蓝就很不爽(,,,虽然做了这题之后又补上了个蓝题QAQ ...

  2. mybatis三剑客之mybatis-pagehelper分页插件

    这是pom.xml里的依赖: 后续再讲具体的使用

  3. java 调用静态方法和构造函数和静态块执行的先后顺序

    构造方法是只有你在new对象的时候才会执行,静态语句块和静态方法在类加载到内存的时候就已经执行了,另外,静态语句块只能给静态变量赋值,里面不能出现方法,同样,静态方法里面也不能出现静态语句块 追问: ...

  4. [WorldWind学习]23.TerrainAccessor

    QuadTile的CreateElevatedMesh()方法中: //获取地形瓦片 TerrainTile tile = QuadTileSet.World.TerrainAccessor.GetE ...

  5. python学习笔记(二十八)日志模块

    我们在写程序的时候经常会打一些日志来帮助我们查找问题,这次学习一下logging模块,在python里面如何操作日志.介绍一下logging模块,logging模块就是python里面用来操作日志的模 ...

  6. php中0与空 Null false的区别

    <?php $test=0; if($test==''){  echo '<br />在php中,0即为空'; //被输出 } if($test===''){  echo '< ...

  7. 001-java虚拟机的概念

    https://blog.csdn.net/yfqnihao/article/details/8289363 1.什么是java虚拟机.(你以为你知道,如果你看我下面的例子,你会发现你其实不知道) ( ...

  8. vue-router的hash模式与history模式的对比

    Vue-router 中hash模式和history模式的关系在vue的路由配置中有mode选项 最直观的区别就是在url中 hash 带了一个很丑的 # 而history是没有#的mode:&quo ...

  9. 2016-2017 ACM-ICPC CHINA-Final Solution

    Problem A. Number Theory Problem Solved. 水. #include<bits/stdc++.h> using namespace std; ; typ ...

  10. zw版【转发·台湾nvp系列Delphi例程】HALCON union1

    zw版[转发·台湾nvp系列Delphi例程]HALCON union1 unit Unit1;interfaceuses Windows, Messages, SysUtils, Variants, ...