Leetcode OJ : Triangle 动态规划 python solution

Total Accepted: 31557 Total Submissions: 116793

 

 

Given a triangle, find the minimum path sum from top to bottom.

Each step you may move to adjacent numbers on the row below.

[
     [2],
    [3,4],
   [6,5,7],
  [4,1,8,3]
]

The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).

Note:
Bonus point if you are able to do this using only O(n) extra space,

where n is the total number of rows in the triangle.

简单的动态规划

 import sys

 class Solution:
     # @param triangle, a list of lists of integers
     # @return an integer
     def minimumTotal(self, triangle):
         length = len(triangle)
         l = [0]
         l.extend([ sys.maxint for x in range(length - 1)])
         def getLastSum(y, x):
             return l[x] if x in range(y+1) else sys.maxint
         for y in range(length):
             for x in range(y, -1, -1):
                 l[x] = triangle[y][x] + min(getLastSum(y, x), getLastSum(y, x - 1))
         return min(l)