[LeetCode&Python] Problem 674. Longest Continuous Increasing Subsequence

Given an unsorted array of integers, find the length of longest continuousincreasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

Example 2:

Input: [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2], its length is 1.

Note: Length of the array will not exceed 10,000.

class Solution(object):
    def findLengthOfLCIS(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        if not nums:
            return 0
        ans=1
        count=1
        n=len(nums)
        i=1
        while i<n:
            if nums[i-1]<nums[i]:
                count+=1
            else:
                if ans<count:
                    ans=count
                count=1
            i+=1
        if ans<count:
            return count
        return ans