AcWing 905. 区间选点

//1.将每个区间按右端点从小到大排序
//2.从前往后依次枚举每个区间，如果当前区间中已经包含点，就直接跳过，否则，选择当前区间的右端点
//选右端点的话，可以尽可能的包含在多个区间里
#include <iostream>
#include <algorithm>
using namespace std;
const int N = ;
int n;
struct Range {
    int l, r;
    bool operator< (const Range &W)const {
        return r < W.r;
    }
} range[N];
int main() {
    scanf("%d", &n);
    for (int i = ; i < n; i ++ ) scanf("%d%d", &range[i].l, &range[i].r);
    sort(range, range + n);
    int res = , ed = -2e9;
    for (int i = ; i < n; i ++ )
        if (range[i].l > ed) {
            res ++ ;
            ed = range[i].r;
        }
    printf("%d\n", res);
    return ;
}