Berland shop sells nn kinds of juices. Each juice has its price cici. Each juice includes some set of vitamins in it. There are three types of vitamins: vitamin "A", vitamin "B" and vitamin "C". Each juice can contain one, two or all three types of vitamins in it.

Petya knows that he needs all three types of vitamins to stay healthy. What is the minimum total price of juices that Petya has to buy to obtain all three vitamins? Petya obtains some vitamin if he buys at least one juice containing it and drinks it.

Input

The first line contains a single integer nn (1≤n≤1000)(1≤n≤1000) — the number of juices.

Each of the next nn lines contains an integer cici (1≤ci≤100000)(1≤ci≤100000) and a string sisi — the price of the ii-th juice and the vitamins it contains. String sisi contains from 11 to 33 characters, and the only possible characters are "A", "B" and "C". It is guaranteed that each letter appears no more than once in each string sisi. The order of letters in strings sisi is arbitrary.

Output

Print -1 if there is no way to obtain all three vitamins. Otherwise print the minimum total price of juices that Petya has to buy to obtain all three vitamins.

Examples
input

Copy
4
5 C
6 B
16 BAC
4 A
output

Copy
15
input

Copy
2
10 AB
15 BA
output

Copy
-1
input

Copy
5
10 A
9 BC
11 CA
4 A
5 B
output

Copy
13
input

Copy
6
100 A
355 BCA
150 BC
160 AC
180 B
190 CA
output

Copy
250
input

Copy
2
5 BA
11 CB
output

Copy
16
Note

In the first example Petya buys the first, the second and the fourth juice. He spends 5+6+4=155+6+4=15 and obtains all three vitamins. He can also buy just the third juice and obtain three vitamins, but its cost is 1616, which isn't optimal.

In the second example Petya can't obtain all three vitamins, as no juice contains vitamin "C".


只有ABC三位,如果按位或是不错的选择

#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
#include <set>
#include <queue>
#include <map>
#include <sstream>
#include <cstdio>
#include <cstring>
#include <numeric>
#include <cmath>
#include<unordered_set>
#define ll long long
using namespace std;
int dir[][] = { {,},{-,},{,},{,-} }; int main()
{
map<string,int> mp;
int n;
cin >> n;
vector<int> dp(,1e9);
dp[] = ;
while (n--)
{
int cost;
string vit;
cin >> cost >> vit;
int m = ;
for (int i = ; i < vit.size(); i++)
m |= << (vit[i] - 'A');
for (int i = ; i < ; i++)
{
dp[i | m] = min(dp[i | m], dp[i] + cost);
}
}
if (dp[] == 1e9)
dp[] = -;
cout << dp[];
//system("pause");
return ;
}

1042B. Vitamins的更多相关文章

  1. CodeForces - 1042B

    Berland shop sells nn kinds of juices. Each juice has its price cici. Each juice includes some set o ...

  2. Codeforces Round #510 (Div. 2) B. Vitamins

    B. Vitamins 题目链接:https://codeforces.com/contest/1042/problem/B 题意: 给出几种药,没种可能包含一种或多种(最多三种)维生素,现在问要吃到 ...

  3. Gym - 101243F Vitamins(思维+并查集)

    题意 有三种药丸,白色W>红色R>蓝色B,给你m个约束条件,问你n个药丸的颜色,不能确定颜色输出‘?’ 题解 如果1<2<3,只要找到2就能确定1和3的颜色 如果2=4,只要确 ...

  4. 【枚举】【并查集】Gym - 101243F - Vitamins

    题意:有n片药,有三种颜色,白色比红色重,红色比蓝色重,给你一些它们之间的重量关系,比如1>3,2=4之类,问你它们的颜色,如果没法判断的输出?. 先并查集把等于号全缩起来,然后按照大于号建图, ...

  5. CF1042B 【Vitamins】(去重,状压搜索)

    由题意,我们其实会发现 对于每一种果汁,其对应的状态只有可能有7种 VA​ VB​ VC​ VA+VB​ VA+VC​ VB+VC​ VA+VB+VC 这道题就大大简化了 我们把所有果汁都读进来 每种 ...

  6. 2018SDIBT_国庆个人第三场

    A - A CodeForces - 1042A There are nn benches in the Berland Central park. It is known that aiai peo ...

  7. 《利用python进行数据分析》读书笔记--第七章 数据规整化:清理、转换、合并、重塑(三)

    http://www.cnblogs.com/batteryhp/p/5046433.html 5.示例:usda食品数据库 下面是一个具体的例子,书中最重要的就是例子. #-*- encoding: ...

  8. HTML & CSS 小总结

    1. web 主机代理商 web hosting company, 让他们的服务器为你的页面服务2. 选择网站名字 例如: www.1234.com3. 寻找 把文件从电脑传到主机的途径4. 把新网站 ...

  9. Diet

    Dialogue 1   Healthy diet 关于健康饮食 F:Bob, look at this sentence. 'Healthy eating is not about strict n ...

随机推荐

  1. 展开折叠效果 height未知 transition无效

    展开折叠效果,没有设置height时 transition 不起作用 可以设置max-height .default { max-height: 500px; transition: all 1000 ...

  2. Gin_Cookie

    1. cookie HTTP是无状态协议,服务器不能记录浏览器的访问状态,也就是说服务器不能区分两次请求是否由同一个客户端发出 Cookie就是解决HTTP协议无状态的方案之一,中文是小甜饼的意思 C ...

  3. [AtCoder Code Festival 2017 QualB D/At3575] 101 to 010 - dp

    [Atcoder Code Festival 2017 QualB/At3575] 101 to 010 有一个01序列,每次可以选出一个101,使其变成010,问最优策略下能操作几次? 考虑像 11 ...

  4. Ubuntu 18.04 怎么安装Gnome Tweak Tool

    地址:https://jingyan.baidu.com/article/86f4a73ebd6c9437d7526963.html 终端键入命令:[sudo add-apt-repository u ...

  5. Accept Xcode/iOS License to run git

    在没有安装Xcode的情况下, 使用了 webstorm 的git,提示 安装xcode,安装完成后,并没有打开xcode,而是再次使用git,发现 提示 输入以下命令行: sudo xcodebui ...

  6. PP: Shallow RNNs: a method for accurate time-series classification on tiny devices

    Problem: time series classification shallow RNNs: the first layer splits the input sequence and runs ...

  7. PHP中关于foreach使用引用变量的坑

    PHP版本为 5.6.12 代码如下:   1 2 3 4 5 6 7 8 9 10 11 12 <?php $arr = ['a', 'b', 'c', 'd', 'e']; foreach ...

  8. 用MyEclipse远程debug

    第一步 编辑 tomcat下的文件startup.sh文件,我的路径是 /root/apache-tomcat-6.0.24/bin/startup.sh 命令:vim startup.sh将decl ...

  9. Mesh R-CNN 论文翻译(实验部分)

    本文为 Mesh R-CNN 论文翻译(原理部分)的后续.Mesh R-CNN 原论文. 4 实验   我们在ShapeNet上对网格预测分支进行基准测试,并与最先进的方法相比较.然后,我们在野生的有 ...

  10. LED Craft Light - How To Solve: Home Decoration Lighting

    Home décor usually comes with a certain period of theme or a specific style of furniture, which will ...