CodeForces 146A Lucky Ticket

Lucky Ticket

Time Limit:2000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Submit Status Practice CodeForces 146A

Description

Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya loves tickets very much. As we know, each ticket has a number that is a positive integer. Its length equals n (n is always even). Petya calls a ticket lucky if the ticket's number is a lucky number and the sum of digits in the first half (the sum of the first n / 2 digits) equals the sum of digits in the second half (the sum of the last n / 2 digits). Check if the given ticket is lucky.

Input

The first line contains an even integer n(2 ≤ n ≤ 50) — the length of the ticket number that needs to be checked. The second line contains an integer whose length equals exactly n — the ticket number. The number may contain leading zeros.

Output

On the first line print "YES" if the given ticket number is lucky. Otherwise, print "NO" (without the quotes).

Sample Input

Input

2
47

Output

NO

Input

4
4738

Output

NO

Input

4
4774

Output

YES

Hint

In the first sample the sum of digits in the first half does not equal the sum of digits in the second half (4 ≠ 7).

In the second sample the ticket number is not the lucky number.

 #include <stdio.h>
 #include <string.h>
 #include <algorithm>
 using namespace std;
 int main()
 {
     char a[];
     int i,j,n;
     while(scanf("%d",&n)!=EOF)
     {
         int flg=,s1=,s2=;
         scanf("%s",a);
         for(i=;i<n;i++)
         {
             if(i<n/)
                 s1=s1+a[i]-'';
             else
                 s2=s2+a[i]-'';
             if(a[i]=='' || a[i]=='')
             {
                 flg=;
             }
             else
             {
                 flg=;
                 break;
             }
         }
         //printf("%d %d\n",s1,s2);
         if(s1!=s2)
             flg=;
         if(flg)
             printf("YES\n");
         else
             printf("NO\n");
     }
     return ;
 }