DataFrame迭代过程中多行修改

方法1：df.loc[conditions]=row.values，逐行地进行整行替换

for row in df.iterrows():
    row['given_amount']=row['amount'];
    row['given_percent']=1
    row['remain_amount']=0
    row['remain_percent']=0
    total_amount=total_amount-row['amount']
    #df_debts.iloc[index]=row #此法不可行，会导致重新迭代。
    df.loc[df['sno']==row['sno']]=row.values

方法2：用loc，批量赋值替换

indexer=df.loc[condition]
df.loc[indexer,'col_1']=new_value
df.loc[indexer,'col_2']=df.loc[indexer,'col_3']*10