2022. Riding a Toad

Time limit: 1.0 second
Memory limit: 64 MB
A tribe of leafmen live in the old forest. Leafmen are very tiny and fast, that’s why we can’t notice them even when they are under our very nose. Leafmen guard the forest unceasingly, protecting it from evil creatures.
A young leafman Nod has occasionally found out that hostile tribe of boggans is planning to make a raid to leafmen’ palace and kidnap their queen. It’s urgent to warn general Ronin about this to make him send his warriors and tighten security of the palace. Nod whistled for his tame hummingbird, but it didn’t appear, it must have had gone hunting on blackflies. Then Nod saddled up a big toad and rode it towards the general’s garrison.

The garrison is surrounded by a wall with width l. On the height h from the ground the wall has a small cylindrical hole with diameter d. This hole is used by leafmen to get inside flying on hummingbirds. But it’s not an easy thing for a toad to jump into it. Then to draw the guards’ attention Nod decides to take a small stone and throw it into the hole while the toad is jumping. The toad is at distance L from the wall and can make one jump with initial speed (vx, vy). At any moment while the toad is in the air and its x coordinate is less than x coordinate of the wall outer surface Nod can throw a stone with an absolute initial speed (ux, uy). The stone should fly into the hole not touching its floor or ceiling. Determine the moment when Nod should throw the stone.
You may assume that both the toad and the stone are not affected by any powers except gravity, giving it down-directed acceleration g.

Input

The first line contains integers L, h, l, d (1 ≤ L, h, l, d ≤ 1000). The second line contains integers vx, vy, ux, uy (1 ≤ vx, vy, ux, uy ≤ 1000). X-axis is horizontal and directed towards the wall, Y-axis is up-directed. Let’s assume gravity acceleration equal 10. All distances are given in meters, all speeds in meters per second.

Output

If Nod can throw the stone into the hole output the moment of time when he should throw it with absolute or relative precision 10−6. The moment of the toad’s take-off should be taken as the initial moment. If there are several moments when it is possible to throw the stone output any of them. Your answer should be such that throwing the stone 10−6 second sooner or later it won’t touch the wall. It is guaranteed that if some answer exists then there is the answer satisfying this constraint. If it is not possible to throw the stone into the hole, output “-1”.

Samples

input output
4 2 2 4
1 1 5 10
0.1
30 15 5 5
10 10 20 10
-1
Problem Author: Nick Burlakov
Problem Source: NEERC 2014, Eastern subregional contest
 
 
 

ural 2022 Riding a Toad的更多相关文章

  1. Toad各版本所包含的组件

    Toad for Oracle Base Edition Toad for Oracle Knowledge Xpert for PL/SQL Knowledge Xpert for Oracle A ...

  2. Toad for Sqlserver

    # 设置制表符 从sqlserver拷贝的存储过程粘贴到Toad,代码变得不整齐了,这就需要设置下制表符的大小.

  3. TOAD和PLSQL 默认日期显示、rowid显示、TNSNAME的修改

    先说下要解决的问题: select rowid,acct_id,state_date from acct; 修改后,1)sql指明rowid,可以显示出来 2)时间格式显示为YYYYMMDD HH24 ...

  4. toad的基本操作

    1.把鼠标停在sql所在行,然后ctrl+Enter直接执行当前sql. 2.解决Toad对中文显示乱码问题(如果数据库所在主机的NLS_LANG是AMERICAN_AMERICA.WE8ISO885 ...

  5. URAL 1966 Cycling Roads 点在线段上、线段是否相交、并查集

    F - Cycling Roads     Description When Vova was in Shenzhen, he rented a bike and spent most of the ...

  6. 后缀数组 POJ 3974 Palindrome && URAL 1297 Palindrome

    题目链接 题意:求给定的字符串的最长回文子串 分析:做法是构造一个新的字符串是原字符串+反转后的原字符串(这样方便求两边回文的后缀的最长前缀),即newS = S + '$' + revS,枚举回文串 ...

  7. ural 2071. Juice Cocktails

    2071. Juice Cocktails Time limit: 1.0 secondMemory limit: 64 MB Once n Denchiks come to the bar and ...

  8. ural 2073. Log Files

    2073. Log Files Time limit: 1.0 secondMemory limit: 64 MB Nikolay has decided to become the best pro ...

  9. ural 2070. Interesting Numbers

    2070. Interesting Numbers Time limit: 2.0 secondMemory limit: 64 MB Nikolay and Asya investigate int ...

随机推荐

  1. Js算两经纬度间球面距离

    function GetDistance( lat1, lng1, lat2, lng2){ var radLat1 = lat1 * Math.PI / 180.0 var radLat2 = la ...

  2. ApexSQL Log 从意外UPDATE和DELETE操作中恢复SQL Server数据

    下载地址:https://www.apexsql.com/download.aspx 如何从意外UPDATE和DELETE操作中恢复SQL Server数据 ApexSQL Log 从意外UPDATE ...

  3. HTTP1.1中CHUNKED编码解析

    一般HTTP通信时,会使用Content-Length头信息性来通知用户代理(通常意义上是浏览器)服务器发送的文档内容长度,该头信息定义于HTTP1.0协议RFC  1945  10.4章节中.浏览器 ...

  4. 升级到tomcat8遇到The method getDispatcherType() is undefined for the type HttpServletRequest

    今天升级到tomcat8,发现原来的项目不能运行了,遇到下面的错误:The method getDispatcherType() is undefined for the type HttpServl ...

  5. mysq数据库的安装和基本操作

    一.数据库的简介 1.什么是数据库? 数据库(database,DB)是指长期存储在计算机内的,有组织,可共享的数据的集合.数据库中的数据按一定的数学模型组织.描述和存储,具有较小的冗余,较高的数据独 ...

  6. 【转】ModelAndView 学习

    http://blog.csdn.net/wavaya/article/details/6185226 ModelAndView 类别就如其名称所示,是代表了Spring Web MVC程式中呈现画面 ...

  7. Protobuf支持 pointf

    Protobuf支持 pointf序列化 加入:ProtoBuf.Meta.RuntimeTypeModel.Default.Add(typeof(System.Drawing.PointF), fa ...

  8. python之路 模块,序列化,迭代器,生成器

    一.模块 1.模块简介 模块是一个包含所有你定义的函数和变量的文件,其后缀名是.py.模块可以被别的程序引入,以使用该模块中的函数等功能.这也是使用python标准库的方法. 类似于函数式编程和面向过 ...

  9. Vimium~让您的Chrome起飞

    工欲善其事,必先利其器!撸起Vimium,我的Chrome就这么起飞了. 学起(了解几个快捷键即可)And撸起Vimium,想黑客一般在Chrome上飞起.Vimium常用快捷键(注:区分大小写)j, ...

  10. 014_HDFS存储架构、架构可靠性分析、副本放置策略、各组件之间的关系

    1.HDFS存储架构