[Codeforces] Alex and a Rhombus
1 second
256 megabytes
standard input
standard output
While playing with geometric figures Alex has accidentally invented a concept of a nn-th order rhombus in a cell grid.
A 11-st order rhombus is just a square 1×11×1 (i.e just a cell).
A nn-th order rhombus for all n≥2n≥2 one obtains from a n−1n−1-th order rhombus adding all cells which have a common side with it to it (look at the picture to understand it better).

Alex asks you to compute the number of cells in a nn-th order rhombus.
The first and only input line contains integer nn (1≤n≤1001≤n≤100) — order of a rhombus whose numbers of cells should be computed.
Print exactly one integer — the number of cells in a nn-th order rhombus.
1
1
2
5
3
13
Images of rhombus corresponding to the examples are given in the statement.
算格子數
就是等差數列 1 + 3 + 5 + ....
最後一塊 last = n * 2 -1; 這個會重複

class Program
{
static void Main(string[] args)
{
Console.WriteLine(Solution.Compute(Convert.ToInt32(Console.ReadLine())));
}
} class Solution
{
public static int Compute(int n)
{
int last = n * - ;
return ( + last) * n - last;
}
}
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参考文档: https://blog.csdn.net/zhihui1017/article/details/50502825