Java [Leetcode 205]Isomorphic Strings
题目描述:
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg", "add", return true.
Given "foo", "bar", return false.
Given "paper", "title", return true.
解题思路:
用数组做映射。注意每次字典映射的时候赋值为i+1,这是为了防止跟第一次映射时候的赋值混淆。(因为数组的初始化赋值为0,若每次赋值为i,那么第一次赋值的时候也为0,这样就混淆了)。
代码如下:
public class Solution {
public boolean isIsomorphic(String s, String t) {
int[] mapS = new int[128];
int[] mapT = new int[128];
for(int i = 0; i < s.length(); i++){
if(mapS[s.charAt(i)] != mapT[t.charAt(i)])
return false;
mapS[s.charAt(i)] = mapT[t.charAt(i)] = i + 1;
}
return true;
}
}
Java [Leetcode 205]Isomorphic Strings的更多相关文章
- [leetcode]205. Isomorphic Strings 同构字符串
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- Java for LeetCode 205 Isomorphic Strings
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- [LeetCode] 205. Isomorphic Strings 解题思路 - Java
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- LeetCode 205. Isomorphic Strings (同构字符串)
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- LeetCode 205 Isomorphic Strings
Problem: Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if ...
- LeetCode 205 Isomorphic Strings(同构的字符串)(string、vector、map)(*)
翻译 给定两个字符串s和t,决定它们是否是同构的. 假设s中的元素被替换能够得到t,那么称这两个字符串是同构的. 在用一个字符串的元素替换还有一个字符串的元素的过程中.所有字符的顺序必须保留. 没有两 ...
- (easy)LeetCode 205.Isomorphic Strings (*)
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- leetcode 205. Isomorphic Strings(哈希表)
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the chara ...
- Leetcode 205 Isomorphic Strings 字符串处理
判断两个字符串是否同构 hs,ht就是每个字符出现的顺序 "egg" 与"add"的数字都是122 "foo"是122, 而"ba ...
随机推荐
- CSS3属性box-shadow使用教程,css3box-shadow
CSS3的box-shadow属性可以让我们轻松实现图层阴影效果.我们来实战详解一下这个属性. 1. box-shadow属性的浏览器兼容性先来看一个这个属性的浏览器兼容性: Opera: 不知道是从 ...
- WCF 之 DataContract
在客户端与服务端之间传递的自定义数据类型,格式如下: [DataContract] public class User :IExtensibleDataObject { [DataMember] pu ...
- 【转载】CCombobox使用大全
一.如何添加/删除Combo Box内容 1. 在Combo Box控件属性的Data标签里面添加,一行表示Combo Box下拉列表中的一行.换行用ctrl+回车. 2. 在程序初始化时动态添加 如 ...
- [C/CPP系列知识] Type difference of character literals 和 bool in C and C++
C/C+中的每一个常亮(every literal)都是有类型的,例如10 就是int型的,因此siziof(10)和sizeof(int)是相同的,但是字符型常亮(‘a’)在C和C++中有不同的变量 ...
- MySQL主从关系设置(转)
来源:LAMP兄弟连 作者:李恺 http://***/php/bencandy.php?fid=70&id=635 要做MySQL主从关系的设置,那么就得有两台MySQL主机.所以在开始之前 ...
- Java学习第五篇:二进制(原码 反码 补码),位运算,移位运算,约瑟夫问题
一.二进制,位运算,移位运算 1.二进制 对于原码, 反码, 补码而言, 需要注意以下几点: (1).Java中没有无符号数, 换言之, Java中的数都是有符号的; (2).二进制的最高位是符号位, ...
- hdu 4324 Triangle LOVE(拓扑排序,基础)
题目 /***************************参考自****************************/ http://www.cnblogs.com/newpanderking ...
- Android 动画的重复播放
如果你要的加载xml方式设置动画,而且在xml定义了好几个动画元素比如:<set> <alpha android:repeatCount="-1" andr ...
- Java中中文拼音的排序问题
最近做一个手机数据同步的应用开发,需要提供地址簿信息按照姓名的拼音次序进行排序.但仔细考察Java提供的Collator之后,发现其中文拼音排序存在严重的问题.Java提供Collator来支持不同语 ...
- 量化Hacker News 中50天的数据 Quantifying Hacker News with 50 days of data
Quantifying Hacker News I thought it would be fun to analyze the activity on one of my favorite sour ...