List remove注意点

public class ListTest {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        List<String> ll = new ArrayList<String>();
        ll.add("1");
        ll.add("2");
        ll.add("3");

        for(String str : ll ){
            if(str.endsWith("2")){
                ll.remove(str);
            }
        }

    }

}

public class ListTest {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        List<String> ll = new ArrayList<String>();
        ll.add("1");
        ll.add("2");
        ll.add("3");

        for(String str : ll ){
            if(str.endsWith("3")){
                ll.remove(str);
            }
        }

    }

}

public class ListTest {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        List<String> ll = new ArrayList<String>();
        ll.add("1");
        ll.add("2");
        ll.add("3");

        for (Iterator it = ll.iterator(); it.hasNext();) {
            String str = (String)it.next();
            if(str.equals("3")){
                it.remove();
                System.out.println(it);
            }else{
                System.out.println(it);
            }
        }

        System.out.println("end");
    }

}

用迭代器就不会有问题：

原因：for是通过指针去判断，如果最后的元素删掉了，那么久没办法判断是否是list结束点了

迭代器的的hasNext()是通过数值判断

public boolean hasNext() {
           return cursor != size();
}  

public E next() {
           checkForComodification();
    try {
    E next = get(cursor);
    lastRet = cursor++;
    return next;
    } catch (IndexOutOfBoundsException e) {
    checkForComodification();
    throw new NoSuchElementException();
    }
}