I-number
以下是真坑爹题目:
此题必须输出前导零,否则永远a不了
I-number
Time Limit: 5000MS Memory limit: 65536K
题目描述
1. y>x;
2. the sum of each
digit of y(under base 10) is the multiple of 10;
3. among all integers that satisfy the two conditions
above, y shouble be the minimum.
Given x, you\'re required to calculate the I-number of
x.
输入
in the first line of input, indicating the number of test cases.
The following T lines
describe all the queries, each with a positive integer x. The length of x will
not exceed 105.
输出
each query.
示例输入
1
202
示例输出
208
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int f[];
int main()
{
int n;
scanf("%d",&n);
{
int i,j;
int ts=;
for(ts=; ts<=n; ts++)
{
memset(f,,sizeof(f));
char g[];
scanf("%s",g);
int t=strlen(g);
for(i=,j=t-; g[i]!='\0'; i++,j--)
f[j]=g[i]-'';
int sum;
while()
{
sum=;
f[]=f[]+;
for(i=; i<=t-;i++)
{
if(f[i]>=)
{
f[i]=f[i]%;
f[i+]=f[i+]+;
}
else break;
}
if(f[t]>)t++;
for(i=;i<=t-;i++)
sum=sum+f[i];
if(sum%==)
{
for(i=t-;i>=;i--)
printf("%d",f[i]);
printf("\n");
break;
}
}
}
}
return ;
}
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