Problem Link:

https://oj.leetcode.com/problems/validate-binary-search-tree/

We inorder-traverse the tree, and for each node we check if current_node.val > prev_node.val. The code is as follows.

# Definition for a  binary tree node
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None class Solution:
# @param root, a tree node
# @return a boolean
def isValidBST(self, root):
stack = []
prev_node = None
p = root
while stack or p:
if p:
stack.append(p)
p = p.left
else:
p = stack.pop()
if prev_node:
if prev_node.val >= p.val:
return False
prev_node = p
p = p.right
return True

【LeetCode OJ】Validate Binary Search Tree的更多相关文章

  1. 【LeetCode练习题】Validate Binary Search Tree

    Validate Binary Search Tree Given a binary tree, determine if it is a valid binary search tree (BST) ...

  2. 【LeetCode OJ】Recover Binary Search Tree

    Problem Link: https://oj.leetcode.com/problems/recover-binary-search-tree/ We know that the inorder ...

  3. LeetCode OJ 98. Validate Binary Search Tree

    Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as ...

  4. LeetCode OJ:Validate Binary Search Tree(合法的二叉搜索树)

    Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as ...

  5. 【LeetCode 99】Recover Binary Search Tree

    Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing ...

  6. 【LeetCode练习题】Recover Binary Search Tree

    Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recove ...

  7. 【leetcode】Validate Binary Search Tree

    Validate Binary Search Tree Given a binary tree, determine if it is a valid binary search tree (BST) ...

  8. Leetcode 笔记 98 - Validate Binary Search Tree

    题目链接:Validate Binary Search Tree | LeetCode OJ Given a binary tree, determine if it is a valid binar ...

  9. 【LeetCode】Validate Binary Search Tree ——合法二叉树

    [题目] Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defin ...

随机推荐

  1. Ajax_showHint() 函数

    showHint() 函数实现的功能是:当用户在输入框中键入字符时,网页如何与 web 服务器进行通信,完整的代码如下: <html><head><script type ...

  2. [转]JavaScript快速检测浏览器对CSS3特性的支持

    转自:https://yuguo.us/weblog/detect-css-support-in-browsers-with-javascript/ ------------------------- ...

  3. SpringMVC流程

    Spring工作流程描述 1. 用户向服务器发送请求,请求被Spring 前端控制Servelt DispatcherServlet捕获: 2. DispatcherServlet对请求URL进行解析 ...

  4. Maven学习链接

    别人的资料很多且写的很详细,我这里先收藏,等学习到一定阶段且有时间再整理自己的积累. 1.eclipse安装maven插件方法: http://blog.csdn.net/kittyboy0001/a ...

  5. Python笔记总结week8

    面向对象第二节 要点: 1. 封装,对象中嵌套对象 2. pickle,load,切记,一定要先导入相关的类 回顾上一节: 面向对象三大特性: 封装.继承.多态(多种类型.多种形态) 关于多态,任意参 ...

  6. opencv用imread( argv[1], 1)读取图片

    显示一幅图:主要是运用功能:imread namedWindow imshowimread:从字面意思我们就可以看懂,用来读取图片的:namedWindow:显然,我们也可以看到这是用来命名窗口名称的 ...

  7. Java--静态区域块

    public class Demo3_2 { static int i=1; static //静态区域块 { //该静态区域块只被执行一次 System.out.println("a&qu ...

  8. winform学习笔记-文档路径

    获取应用程序路径 //获取当前进程的完整路径,包含文件名(进程名).string str = this.GetType().Assembly.Location;result: X:\xxx\xxx\x ...

  9. java动手动脑和课后实验型问题String类型

    1.请运行以下示例代码StringPool.java,查看其输出结果.如何解释这样的输出结果?从中你能总结出什么? true true false 总结: 使用new关键字创建字符串对象时, 每次申请 ...

  10. NOIP2016之反面教材提供

    NOIP 2016信息竞赛总结 竞赛历程总结: 算下来一共学了11个月的信息竞赛,从最初进来的时候大概会一点最最基础的语法,上课什么也听不懂,然后一直追进度,我想在这个阶段中我的问题主要是自己知道自己 ...