The computer company you work for is introducing a brand new computer line and is developing a new Unix-like operating system to be introduced along with the new computer. Your assignment is to write the formatter for the ls function.

Your program will eventually read input from a pipe (although for now your program will read from the input file). Input to your program will consist of a list of (F) filenames that you will sort (ascending based on the ASCII character values) and format into (C) columns based on the length (L) of the longest filename. Filenames will be between 1 and 60 (inclusive) characters in length and will be formatted into left-justified columns. The rightmost column will be the width of the longest filename and all other columns will be the width of the longest filename plus 2. There will be as many columns as will fit in 60 characters. Your program should use as few rows (R) as possible with rows being filled to capacity from left to right.

Input

The input file will contain an indefinite number of lists of filenames. Each list will begin with a line containing a single integer (1 N 100). There will then be N lines each containing one left-justified filename and the entire line’s contents (between 1 and 60 characters) are considered to be part of the filename. Allowable characters are alphanumeric (a to z, A to Z, and 0 to 9) and from the following set {._-} (not including the curly braces). There will be no illegal characters in any of the filenames and no line will be completely empty.

Immediately following the last filename will be the N for the next set or the end of file. You should read and format all sets in the input file.

Output

For each set of filenames you should print a line of exactly 60 dashes (-) followed by the formatted columns of filenames. The sorted filenames 1 to R will be listed down column 1; filenames R + 1 to 2R listed down column 2; etc.

Sample Input

10

tiny

2short4me

very_long_file_name

shorter

size-1

size2

size3

much_longer_name

12345678.123

mid_size_name

12

Weaser

Alfalfa

Stimey

Buckwheat

Porky

Joe

Darla

Cotton

Butch

Froggy

Mrs_Crabapple

P.D.

19

Mr._French

Jody

Buffy

Sissy

Keith

Danny

Lori

Chris

Shirley

Marsha

Jan

Cindy

Carol

Mike

Greg

Peter

Bobby

Alice

Ruben

Sample Output

12345678.123 size-1

2short4me size2

mid_size_name size3

much_longer_name tiny

shorter very_long_file_name

Alfalfa Cotton Joe Porky

Buckwheat Darla Mrs_Crabapple Stimey

Butch Froggy P.D. Weaser

Alice Chris Jan Marsha Ruben

Bobby Cindy Jody Mike Shirley

Buffy Danny Keith Mr._French Sissy

Carol Greg Lori Peter

排好后从左开始一列一列向下打印,前面的要最大长度加2,最后一列是最大长度,总长度不大于60

题目看错,改了一万年

#include<iostream>
#include<stdio.h>
#include<stdlib.h>
#include <iomanip>
#include<cmath>
#include<string.h>
#include<algorithm>
#define sf scanf
#define pf printf
#define pb push_back
#define mm(x,b) memset((x),(b),sizeof(x))
#include<vector>
#include<map>
//#define for(i,a,b) for(int i=a;i<b;i++)
typedef long long ll;
typedef long double ld;
const ll mod=1e9+7;
using namespace std;
const double pi=acos(-1.0);
int max(int a,int b){return a>b?a:b;} void first()
{
for(int i=0;i<60;i++)
pf("-");
pf("\n");
}
int main()
{
// f reopen("output1.txt", "r", stdin);
int n;
cout.setf(std::ios::left);
while(~sf("%d",&n))
{
// getchar(); string a[105];
int Max=0;
for(int i=0;i<n;i++)
{
cin>>a[i];
Max=max(Max,a[i].size());
}
first();
int m=(60-Max)/(Max+2)+1;//m是确定一行多少个
int sum=n/m;//sum是多少行
int ans=n%m;//ans是最后一行多少列
int i=1,time=0,temp=0;
if(ans) sum++;
sort(a,a+n);
for(int i=0;i<sum;i++)
{
for(int j=0;j<m;j++)
{
if(j*sum+i+1>n) break;
if(j==m-1)
cout<<setfill(' ')<<setw(Max)<<a[j*sum+i];
else
cout<<setfill(' ')<<setw(Max+2)<<a[j*sum+i];
}
cout<<endl;
} }
return 0;
}

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