uva-704-暴力枚举-双向bfs
题意:俩个转盘,24个数字,每个转盘都可以顺时针,逆时针旋转.终点固定.
问:给定一个起点,能不能在16步内转到终点
解法:双向bfs,终点走8步,起点走8步,判断从起点生成的状态是否在终点里面,如果在即是有解
注意题目要输出转动的方向,并且方向字符串要最小,所以,在某一步有解事,要把当前层数走完,取最小值
#include <iostream>
#include<map>
#include<memory.h>
#include<stdio.h>
#include<string>
#include<queue> using namespace std; const int MAXN = ; string zhuan(string str, int way)
{
string reStr(str);
if (way == )
{
//左边顺时针旋转
char sb1 = str[];
char sb2 = str[];
for (int i = ;i >= ;i--)
reStr[i] = reStr[i - ];
reStr[] = sb2;
reStr[] = sb1;
reStr[] = reStr[];
reStr[] = reStr[];
reStr[] = reStr[];
}
else if (way == )
{
//左边逆时针旋转
char sb1 = reStr[];
char sb2 = reStr[];
for (int i = ;i < ;i++)
reStr[i] = reStr[i + ];
reStr[] = sb2;
reStr[] = sb1;
reStr[] = reStr[];
reStr[] = reStr[];
reStr[] = reStr[];
}
else if (way == )
{
//右边顺时针旋转
char sb1 = reStr[];
char sb2 = reStr[];
for (int i = ;i < ;i++)
reStr[i] = reStr[i + ];
reStr[] = sb2;
reStr[] = sb1;
reStr[] = reStr[];
reStr[] = reStr[];
reStr[] = reStr[];
}
else
{
//右边逆时针旋转
char sb1 = reStr[];
char sb2 = reStr[];
for (int i = ;i >= ;i--)
reStr[i] = reStr[i - ];
reStr[] = sb2;
reStr[] = sb1;
reStr[] = reStr[];
reStr[] = reStr[];
reStr[] = reStr[];
}
return reStr;
} class Node
{
public:
string str;
string step;
int stepNum;
bool operator < (const Node& node) const
{
return stepNum > node.stepNum;
}
}; const static string endState = "034305650121078709a90121";
map<string, string> sMap;
map<string, string>eMap;
priority_queue<Node> q; int ok = ;
string curStep = ""; string path(string es)
{
string str = "";
for (int i = es.size() - ; i >= ;i--)
{
if (es.at(i) == '') str+= "";
else if (es.at(i) == '') str += "";
else if (es.at(i) == '')str += "";
else if (es.at(i) == '') str += "";
}
return str;
} //
void bfsEnd()
{
while (!q.empty())
q.pop();
Node n;
n.step = "";
n.stepNum = ;
n.str = endState;
q.push(n);
eMap[endState] = "";
while (!q.empty())
{
n = q.top();
q.pop();
if (n.stepNum == )
break;
for (int i=;i<=;i++)
{
string str = zhuan(n.str, i);
if (eMap.find(str) == eMap.end())
{
string sstep(n.step);
sstep += i + '';
Node nn;
nn.stepNum = n.stepNum + ;
nn.str = str;
nn.step = sstep;
q.push(nn);
eMap[str] = sstep;
}
}
}
} void bfsStart(string str)
{
while (!q.empty())
q.pop();
Node n;
n.step = "";
n.stepNum = ;
n.str = str;
q.push(n);
int okStep = INT32_MAX;
while (!q.empty())
{
n = q.top();
q.pop();
if (ok && n.stepNum != okStep)
break;
if (eMap.find(n.str) != eMap.end())
{
if (ok == )
{
curStep = n.step+path(eMap.find(n.str)->second);
okStep = n.stepNum;
ok = ;
}
else
{
string step = n.step + path(eMap.find(n.str)->second);
//判断大小
if (strcmp(curStep.c_str(), step.c_str()) > )
curStep = step;
}
}
if (ok)
continue;
for (int i = ; i <= && n.stepNum != ; i++)
{
str = zhuan(n.str,i);
if (sMap.find(str) == sMap.end())
{
string sstep(n.step);
sstep += i + '';
Node nn;
nn.stepNum = n.stepNum + ;
nn.str = str;
nn.step = sstep;
sMap[str] = sstep;
q.push(nn);
}
}
} }
int main()
{ int k = ;
cin >> k;
eMap.clear();
bfsEnd();
while (k--)
{
ok = ;
sMap.clear();
string str = "";
int j;
for (int i = ;i < MAXN;++i)
{
cin >> j;
if (j == )
str += 'a';
else
str += j + '';
} if (str == endState)
{
cout << "PUZZLE ALREADY SOLVED" << endl;
continue;
}
bfsStart(str);
if (ok==)
{
cout << "NO SOLUTION WAS FOUND IN 16 STEPS" << endl;
continue;
}
cout << curStep << endl; } }
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