Determine whether an integer is a palindrome. Do this without extra space.

分析:把一个数倒过来,然后看两个数是否相同。

 public class Solution {
public boolean isPalindrome(int x) {
if (x < ) {
return false;
}
long palindromeX = , inputX = x;
while (x > ) {
palindromeX = palindromeX * + (x % );
x = x / ;
}
return palindromeX == inputX;
}
}

Reverse digits of an integer.

Example1: x = 123, return 321
Example2: x = -123, return -321

Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231,  231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

 public class Solution {
public int reverse(int x) {
boolean isPositive = true; if (x < ) {
x = -x;
isPositive = false;
} long reversedValue = ;
while (x != ) {
reversedValue = reversedValue * + x % ;
x /= ;
}
if (Math.abs(reversedValue) > Integer.MAX_VALUE) return ; return isPositive ? (int)reversedValue : (int)(-reversedValue);
}
}

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