Pre- and Post-order Traversals

PAT-1119

  • 这题难度较大,主要需要考虑如何实现根据前序遍历和后序遍历来确定一颗二叉树
  • 一篇好的文章: 题解
import java.util.Scanner;

/**
* @Author WaleGarrett
* @Date 2020/9/5 18:04
*/
public class PAT_1119 {
static int[] preorder;
static int[] postorder;
static boolean flag=true;//判断二叉树是否唯一
public static void main(String[] args) {
Scanner scanner=new Scanner(System.in);
int n=scanner.nextInt();
preorder=new int[n];
postorder=new int[n];
for(int i=0;i<n;i++){
preorder[i]=scanner.nextInt();
}
for(int i=0;i<n;i++){
postorder[i]=scanner.nextInt();
}
PPNode root=buildTree(0,n-1,0,n-1);
if(flag){
System.out.println("Yes");
}else System.out.println("No");
System.out.println(inOrder(root,"").trim());
}
public static PPNode buildTree(int prel,int prer,int postl,int postr){
PPNode root=new PPNode();
root.value=preorder[prel];
if(prel>=prer)
return root;
// System.out.println(prel+" "+prer);
int position=0;
if(prel<prer&&preorder[prel+1]==postorder[postr-1]){
flag=false;//不唯一
//默认为左子树
root.left=buildTree(prel+1,prer,postl,postr-1);
}else{
for(int i=postl;i<postr;i++){
// System.out.println(i+" "+(prel+1));
if(postorder[i]==preorder[prel+1]){
position=i;
break;
}
}
int numl=position-postl+1;
root.left=buildTree(prel+1,prel+numl,postl,position);
root.right=buildTree(prel+numl+1,prer,position+1,postr-1);
}
return root;
}
public static String inOrder(PPNode root,String result){
if(root.left!=null)
result=inOrder(root.left,result);
result=result+root.value+" ";
if(root.right!=null){
result=inOrder(root.right,result);
}
return result;
}
}
class PPNode{
PPNode left;
PPNode right;
int value;
public PPNode(){
left=right=null;
value=-1;
}
}

PAT-1119(Pre- and Post-order Traversals)+前序和后序遍历确定二叉树+判断二叉树是否唯一的更多相关文章

  1. [Swift]LeetCode889. 根据前序和后序遍历构造二叉树 | Construct Binary Tree from Preorder and Postorder Traversal

    Return any binary tree that matches the given preorder and postorder traversals. Values in the trave ...

  2. [二叉树建树]1119. Pre- and Post-order Traversals (30) (前序和后序遍历建立二叉树)

    1119. Pre- and Post-order Traversals (30) Suppose that all the keys in a binary tree are distinct po ...

  3. 笔试算法题(36):寻找一棵二叉树中最远节点的距离 & 根据二叉树的前序和后序遍历重建二叉树

    出题:求二叉树中距离最远的两个节点之间的距离,此处的距离定义为节点之间相隔的边数: 分析: 最远距离maxDis可能并不经过树的root节点,而树中的每一个节点都可能成为最远距离经过的子树的根节点:所 ...

  4. LeetCode OJ:Construct Binary Tree from Preorder and Inorder Traversal(从前序以及中序遍历结果中构造二叉树)

    Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that ...

  5. PAT 甲级 1043 Is It a Binary Search Tree (25 分)(链表建树前序后序遍历)*不会用链表建树 *看不懂题

    1043 Is It a Binary Search Tree (25 分)   A Binary Search Tree (BST) is recursively defined as a bina ...

  6. POJ 1240 Pre-Post-erous! && East Central North America 2002 (由前序后序遍历序列推出M叉树的种类)

    题目链接 问题描述 : We are all familiar with pre-order, in-order and post-order traversals of binary trees. ...

  7. 剑指offer面试题:输入某二叉树的前序遍历和中序遍历,输出后序遍历

    二叉树的先序,中序,后序如何遍历,不在此多说了.直接看题目描述吧(题目摘自九度oj剑指offer面试题6): 输入某二叉树的前序遍历和中序遍历的结果,请重建出该二叉树.假设输入的前序遍历和中序遍历的结 ...

  8. POJ 1240 Pre-Post-erous! && East Central North America 2002 (由前序后序遍历序列推出M叉树的种类)

    题目链接:http://poj.org/problem?id=1240 本文链接:http://www.cnblogs.com/Ash-ly/p/5482520.html 题意: 通过一棵二叉树的中序 ...

  9. 二叉树:前序遍历、中序遍历、后序遍历,BFS,DFS

    1.定义 一棵二叉树由根结点.左子树和右子树三部分组成,若规定 D.L.R 分别代表遍历根结点.遍历左子树.遍历右子树,则二叉树的遍历方式有 6 种:DLR.DRL.LDR.LRD.RDL.RLD.由 ...

随机推荐

  1. Codeforces Round #613 (Div. 2) C. Fadi and LCM (数学)

    题意:给你一个正整数\(x\),找两个正整数\(a\),\(b\),使得\(lcm(a,b)=x\),并且\(max(a,b)\)最小. 题解:我们知道,\(lcm(a,b)=a*b/gcd(a,b) ...

  2. Codeforces Round #479 (Div. 3) D. Divide by three, multiply by two (DFS)

    题意:给你一个长度为\(n\)的序列\(a\).对它重新排列,使得\(a_{i+1}=a_{i}/3\)或\(a_{i+1}=2*a_{i}\).输出重新排列后的序列. 题解:经典DFS,遍历这个序列 ...

  3. CF1466-D. 13th Labour of Heracles

    CF1466-D. 13th Labour of Heracles 题意: 给出一个由\(n\)个点构成的树,每个点都有一个权值.现在你可以用\(k,k\subset\)\([1, n]\)个颜色来给 ...

  4. C- c常见问题分析

    一.遇到undefined symbol怎么办: (1)首先解析未定义符号是什么:[利用c++filt命令] c++filt _ZN4Json5ValueixERKNSt7__cxx1112basic ...

  5. pthread_create函数

    函数简介 pthread_create是UNIX环境创建线程函数 头文件 #include<pthread.h> 函数声明 int pthread_create(pthread_t *re ...

  6. C# 类(3)

    方法重载 和python类似,在调用函数的时候可以指定默认参数,car("Jeep",color="red") 方法重载就是 可以定义几个同名的函数,然后带有不 ...

  7. 阅文集团 招聘官网 bug

    阅文集团 招聘官网 bug https://join.yuewen.com/ 前端开发 zxx.jpg 张鑫旭 https://qidian.gtimg.com/yuewen/join/css/ima ...

  8. shit 牛客网

    shit 牛客网 为什么,只可以 log 一次,什么垃圾逻辑呀! https://www.nowcoder.com/test/question/e46437833ddc4c5bb79f7af7a1b7 ...

  9. CSS3 & Grid Layout All In One

    CSS3 & Grid Layout All In One W3C https://www.w3.org/TR/css-grid-1/ Grid Layout is a new layout ...

  10. npx & yarn & npm

    npx & yarn & npm React Redux App https://reactjs.org/ https://github.com/facebook/create-rea ...