Given a string S, count the number of distinct, non-empty subsequences of S .

Since the result may be large, return the answer modulo 10^9 + 7.

Example 1:

Input: "abc"
Output: 7
Explanation: The 7 distinct subsequences are "a", "b", "c", "ab", "ac", "bc", and "abc".

Example 2:

Input: "aba"
Output: 6
Explanation: The 6 distinct subsequences are "a", "b", "ab", "ba", "aa" and "aba".

Example 3:

Input: "aaa"
Output: 3
Explanation: The 3 distinct subsequences are "a", "aa" and "aaa".

Note:

  1. S contains only lowercase letters.
  2. 1 <= S.length <= 2000

Approach #1: Math. [Java]

class Solution {
public int distinctSubseqII(String S) {
long end[] = new long[26], mod = (long)1e9 + 7;
for (char c : S.toCharArray())
end[c - 'a'] = Arrays.stream(end).sum()%mod + 1;
return (int)(Arrays.stream(end).sum()%mod);
}
}

  

Analysis:

Reference:

https://www.jianshu.com/p/02501f516437

940. Distinct Subsequences II的更多相关文章

  1. 【leetcode】940. Distinct Subsequences II

    题目如下: Given a string S, count the number of distinct, non-empty subsequences of S . Since the result ...

  2. 【LeetCode】940. Distinct Subsequences II 解题报告(Python)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 日期 题目地址:https://leetc ...

  3. [Swift]LeetCode940. 不同的子序列 II | Distinct Subsequences II

    Given a string S, count the number of distinct, non-empty subsequences of S . Since the result may b ...

  4. [LeetCode] Distinct Subsequences 不同的子序列

    Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence ...

  5. Distinct Subsequences

    https://leetcode.com/problems/distinct-subsequences/ Given a string S and a string T, count the numb ...

  6. Leetcode Distinct Subsequences

    Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence ...

  7. LeetCode(115) Distinct Subsequences

    题目 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequen ...

  8. [Leetcode][JAVA] Distinct Subsequences

    Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence ...

  9. Distinct Subsequences Leetcode

    Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence ...

随机推荐

  1. 表单提交的两种请求方式:post与get。post与get两者的对比分析

    post与get两者的对比分析:

  2. Spring框架的事务管理之声明式事务管理的类型

    1. 声明式事务管理又分成两种方式 * 基于AspectJ的XML方式(重点掌握)(具体内容见“https://www.cnblogs.com/wyhluckdog/p/10137712.html”) ...

  3. sql优化常用命令总结

    1.显示执行计划的详细步骤 SET SHOWPLAN_ALL ON; SET SHOWPLAN_ALL OFF; 2. 显示执行语句的IO成本,时间成本 SET STATISTICS IO ON SE ...

  4. codevs1246 丑数

    题目描述 Description 对于一给定的素数集合 S = {p1, p2, ..., pK}, 来考虑那些质因数全部属于S 的数的集合.这个集合包括,p1, p1p2, p1p1, 和 p1p2 ...

  5. Hadoop 系列(一)基本概念

    Hadoop 系列(一)基本概念 一.Hadoop 简介 Hadoop 是一个由 Apache 基金会所开发的分布式系统基础架构,它可以使用户在不了解分布式底层细节的情況下开发分布式程序,充分利用集群 ...

  6. OSGi 系列(三)之 bundle 事件监听

    OSGi 系列(三)之 bundle 事件监听 bundle 的事件监听是在 bundle 生命周期的不同状态相互转换时,OSGi 框架会发出各种不同的事件供事先注册好的事件监听器处理. 1. 事件监 ...

  7. 动态加载页面 通过src

    <img src="a.jpg"> 通过js  改变 src 路径 如action  路径, 注意 action 配置问题.

  8. Core Dump 程序故障分析

    1.编写一个应用程序,使用gdb+core dump进行故障分析, core dump的概念: core dump又叫核心转存:当程序在运行过程中发生异常,这时Linux系统可以把程序在运行时的内存内 ...

  9. 创建DB2数据库联合对象

    db2 1.db2 =>update dbm cfg using Federated YES 2. db2 =>db2stop force3. db2 =>db2start 4.创建 ...

  10. 2018.09.17 atcoder Tak and Hotels(贪心+分块)

    传送门 一道有意思的题. 一开始想错了,以为一直lowerlowerlower_boundboundbound就可以解决询问,结果交上去TLE了之后才发现时间复杂度是错的. 但是贪心思想一定是对的,每 ...