这个题目是典型的KMP算法,当然也可以试试BM,当然有关KMP和BM的介绍阮一峰曾经写过比较好的科普,然后july也有讲解,不过那个太长了。

先放题目吧:

Implement strStr().

Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack.

Update (2014-11-02):

The signature of the function had been updated to return the index instead of the pointer. If you still see your function signature returns a char * or String, please click the reload button to reset your code definition.

就是找到haystack内是否有needle这个字符串,字符串查找算法。

KMP主要是建立一个next的部分匹配数组,来用空间换时间。next的生成函数是KMP关键,解法如下:

class Solution {
public:
vector<int> generateNext(char *str)
{
int len = strlen(str);
vector<int> tmp;
tmp.push_back(0); for (int i = 1, j = 0; i < len; i++)
{
while (j > 0 && str[i] != str[j])
{
j = tmp.at(j - 1);
} if (str[i] == str[j])
{
j++;
} tmp.push_back(j);
} return tmp;
} int strStr(char *haystack, char *needle)
{
vector<int> next = generateNext(needle); int lenH = strlen(haystack);
int lenN = strlen(needle); if (lenN == 0)
{
return 0;
}
if (lenH < lenN)
{
return -1;
}
int i, j; for (i = 0, j = 0; i < lenH; i++)
{
while (j > 0 && haystack[i] != needle[j])
{
j = next[j - 1];
} if (haystack[i] == needle[j])
{
j++;
} if (j == lenN)
{
return i - lenN + 1;
}
}
return -1;
}
};

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