hdu6208 The Dominator of Strings
地址:
题目:
The Dominator of Strings
Time Limit: 3000/3000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 857 Accepted Submission(s): 264
For each test case, the first line contains an integer N indicating the size of the set.
Each of the following N lines describes a string of the set in lowercase.
The total length of strings in each case has the limit of 100000.
The limit is 30MB for the input file.
10
you
better
worse
richer
poorer
sickness
health
death
faithfulness
youbemyweddedwifebetterworsericherpoorersicknesshealthtilldeathdouspartandpledgeyoumyfaithfulness
5
abc
cde
abcde
abcde
bcde
3
aaaaa
aaaab
aaaac
abcde
No
#include <queue>
#include <cstring>
#include <cstdio>
#include <string>
#include <iostream>
using namespace std; struct AC_auto
{
const static int LetterSize = ;
const static int TrieSize = * ( 1e5 + ); int tot,root,fail[TrieSize],end[TrieSize],next[TrieSize][LetterSize]; int newnode(void)
{
memset(next[tot],-,sizeof(next[tot]));
end[tot] = ;
return tot++;
} void init(void)
{
tot = ;
root = newnode();
} int getidx(char x)
{
return x - 'a';
} void insert(string &ss)
{
int len = ss.length();
int now = root;
for(int i = ; i < len; i++)
{
int idx = getidx(ss[i]);
if(next[now][idx] == -)
next[now][idx] = newnode();
now = next[now][idx];
}
end[now]++;
} void build(void)
{
queue<int>Q;
fail[root] = root;
for(int i = ; i < LetterSize; i++)
if(next[root][i] == -)
next[root][i] = root;
else
fail[next[root][i]] = root,Q.push(next[root][i]);
while(Q.size())
{
int now = Q.front();Q.pop();
for(int i = ; i < LetterSize; i++)
if(next[now][i] == -) next[now][i] = next[fail[now]][i];
else
fail[next[now][i]] = next[fail[now]][i],Q.push(next[now][i]);
}
} int match(string &ss)
{
int len,now,res;
len = ss.length(),now = root,res = ;
for(int i = ; i < len; i++)
{
int idx = getidx(ss[i]);
int tmp = now = next[now][idx];
while(tmp)
{
res += end[tmp];
end[tmp] = ;//按题目修改
tmp = fail[tmp];
}
}
return res;
}
void debug()
{
for(int i = ;i < tot;i++)
{
printf("id = %3d,fail = %3d,end = %3d,chi = [",i,fail[i],end[i]);
for(int j = ;j < LetterSize;j++)
printf("%3d",next[i][j]);
printf("]\n");
}
}
};
AC_auto ac;
string ss[];
int main(void)
{
std::ios::sync_with_stdio();
cin.tie();
//freopen("in.acm","r",stdin);
int t,n,id;cin>>t;
while(t--)
{
id=;
ac.init();
cin>>n>>ss[];
for(int i=;i<=n;i++) cin>>ss[i],id=ss[id].length()>ss[i].length()?id:i;
for(int i=;i<=n;i++)
if(i!=id)
ac.insert(ss[i]);
ac.build();
if(ac.match(ss[id])==n-)
cout<<ss[id]<<"\n";
else
cout<<"No\n";
}
return ;
}
sam做法:
#include <bits/stdc++.h> using namespace std; struct SAM
{
static const int MAXN = <<;//大小为字符串长度两倍
static const int LetterSize = ; int tot, last, ch[MAXN][LetterSize], fa[MAXN], len[MAXN];
int sum[MAXN], tp[MAXN], cnt[MAXN]; //sum,tp用于拓扑排序,tp为排序后的数组 void init( void)
{
last = tot = ;
len[] = ;
memset(ch[],,sizeof ch[]);
memset(cnt,,sizeof cnt);
} void add(int x)
{
int p = last, np = last = ++tot;
len[np] = len[p] + , cnt[last] = ;
memset(ch[np],,sizeof ch[np]);
while( p && !ch[p][x]) ch[p][x] = np, p = fa[p];
if( p == )
fa[np] = ;
else
{
int q = ch[p][x];
if( len[q] == len[p] + )
fa[np] = q;
else
{
int nq = ++tot;
memcpy( ch[nq], ch[q], sizeof ch[q]);
len[nq] = len[p] + , fa[nq] = fa[q], fa[q] = fa[np] = nq;
while( p && ch[p][x] == q) ch[p][x] = nq, p = fa[p];
}
}
} void toposort( void)
{
for(int i = ; i <= len[last]; i++) sum[i] = ;
for(int i = ; i <= tot; i++) sum[len[i]]++;
for(int i = ; i <= len[last]; i++) sum[i] += sum[i-];
for(int i = ; i <= tot; i++) tp[sum[len[i]]--] = i;
for(int i = tot; i; i--) cnt[fa[tp[i]]] += cnt[tp[i]];
} bool match(string &s)
{
for(int i=,p=;i<s.length();p=ch[p][s[i]-'a'],i++)
if(!ch[p][s[i]-'a'])
return ;
return ;
}
} sam;
string ss[];
int main(void)
{
ios::sync_with_stdio();
cin.tie();
int t;cin>>t;
while(t--)
{
int n,ff=,id=;
cin>>n;
for(int i=;i<=n;i++) cin>>ss[i],id=(ss[i].length()>ss[id].length()?i:id);
sam.init();
for(int i=;i<=n;i++)
if(i!=id)
{
for(int j=;j<ss[i].length();j++) sam.add(ss[i][j]-'a');
sam.add();
}
for(int i=n;i&&ff;i--)
if(i!=id&&!sam.match(ss[i]))
ff=;
if(ff) cout<<ss[id]<<"\n";
else cout<<"No\n";
}
return ;
}
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