LeetCode 232 Implement Queue using Stacks
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Notes:
- You must use only standard operations of a stack -- which means only
push to top,peek/pop from top,size, andis emptyoperations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
- You must use only standard operations of a stack -- which means only
思路:
利用两个栈,每次入队的操作时,将一个栈中的元素全部弹出,后在有元素的栈中压入入队元素,后将该栈的全部元素弹出,压回第一个栈中即可。
解法:
import java.util.Stack;
public class MyQueue
{
private Stack<Integer> inputStack;
private Stack<Integer> outputStack;
public MyQueue()
{
inputStack = new Stack<>();
outputStack = new Stack<>();
}
public void push(int x)
{
while(!outputStack.isEmpty())
inputStack.push(outputStack.pop());
inputStack.push(x);
while(!inputStack.isEmpty())
outputStack.push(inputStack.pop());
}
public void pop()
{ outputStack.pop(); }
public int peek()
{ return outputStack.peek(); }
public boolean empty()
{ return outputStack.isEmpty(); }
}
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