LeetCode 232 Implement Queue using Stacks
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
Notes:
- You must use only standard operations of a stack -- which means only
push to top
,peek/pop from top
,size
, andis empty
operations are valid. - Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
- You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).
- You must use only standard operations of a stack -- which means only
思路:
利用两个栈,每次入队的操作时,将一个栈中的元素全部弹出,后在有元素的栈中压入入队元素,后将该栈的全部元素弹出,压回第一个栈中即可。
解法:
import java.util.Stack; public class MyQueue { private Stack<Integer> inputStack; private Stack<Integer> outputStack; public MyQueue() { inputStack = new Stack<>(); outputStack = new Stack<>(); } public void push(int x) { while(!outputStack.isEmpty()) inputStack.push(outputStack.pop()); inputStack.push(x); while(!inputStack.isEmpty()) outputStack.push(inputStack.pop()); } public void pop() { outputStack.pop(); } public int peek() { return outputStack.peek(); } public boolean empty() { return outputStack.isEmpty(); } }
LeetCode 232 Implement Queue using Stacks的更多相关文章
- Leetcode 232 Implement Queue using Stacks 和 231 Power of Two
1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元 ...
- [LeetCode] 232. Implement Queue using Stacks 用栈来实现队列
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...
- (easy)LeetCode 232.Implement Queue using Stacks
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...
- Java [Leetcode 232]Implement Queue using Stacks
题目描述: Implement the following operations of a queue using stacks. push(x) -- Push element x to the b ...
- Java for LeetCode 232 Implement Queue using Stacks
Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); } // ...
- Leetcode 232 Implement Queue using Stacks STL
本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa ...
- LeetCode 232 Implement Queue using Stacks 两个栈实现队列
class MyQueue { public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x ...
- leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues
155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...
- 232. Implement Queue using Stacks,225. Implement Stack using Queues
232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...
随机推荐
- 【Spring】Redis的两个典型应用场景--good
原创 BOOT Redis简介 Redis是目前业界使用最广泛的内存数据存储.相比memcached,Redis支持更丰富的数据结构,例如hashes, lists, sets等,同时支持数据持久化. ...
- Ubuntu下的svn的安装
安装SVN问题很多,现在目前遇到的问题是,安装时候找不到svn connector的连接器 导致不能够对SVN插件进行完整安装.但是可以单独安装该插件 http://community.pol ...
- Ubuntu使用总结
错误 鼠标闪烁解决 系统设置->显示—>未知显示器->关闭->应用->选择当前配置 提示sudo: unable to resolve host ,亦即无法解析主机. 原 ...
- vpn局域网共享
vpn局域网共享 更改网关为vpn共享主机地址 在“命令运行符”处,挨个键入下列命令,并回车生效: regsvr32 Softpub.dll regsvr32 Wintrust.dll regsvr3 ...
- 进程间通信机制<转>
1 文件映射 文件映射(Memory-Mapped Files)能使进程把文件内容当作进程地址区间一块内存那样来对待.因此,进程不必使用文件I/O操作,只需简单的指针操作就可读取和修改文件的内容. ...
- HDU 1698 Just a Hook (线段树 成段更新 lazy-tag思想)
题目链接 题意: n个挂钩,q次询问,每个挂钩可能的值为1 2 3, 初始值为1,每次询问 把从x到Y区间内的值改变为z.求最后的总的值. 分析:用val记录这一个区间的值,val == -1表示这 ...
- HDU 1397 Goldbach's Conjecture【素数打表】
题意:给出n,问满足a+b=n且a,b都为素数的有多少对 将素数打表,再枚举 #include<iostream> #include<cstdio> #include<c ...
- WebApp开发框架Ionic+AngularJS+Cordova
目前的手机APP有三类:原生APP.WebAPP.HybridApp:HybridApp结合了前两类APP各自的优点,越来越流行. Ionic Ionic是一个新的.可以使用HTML5构建混合移动应用 ...
- codevs 1172 Hankson 的趣味题
woc....这题考细节处理.要注意代码的逻辑顺序还有不要作死地循环到sqrt+1. #include<iostream> #include<cstdio> #include& ...
- RTP头结构解析
RTP包头前12个固定字节机构图: 0 1 2 3 0 1 2 3 4 5 6 7 8 9 ...