Implement the following operations of a queue using stacks.

  • push(x) -- Push element x to the back of queue.
  • pop() -- Removes the element from in front of queue.
  • peek() -- Get the front element.
  • empty() -- Return whether the queue is empty.

    Notes:

    • You must use only standard operations of a stack -- which means only push to toppeek/pop from topsize, and is empty operations are valid.
    • Depending on your language, stack may not be supported natively. You may simulate a stack by using a list or deque (double-ended queue), as long as you use only standard operations of a stack.
    • You may assume that all operations are valid (for example, no pop or peek operations will be called on an empty queue).

思路:

利用两个栈,每次入队的操作时,将一个栈中的元素全部弹出,后在有元素的栈中压入入队元素,后将该栈的全部元素弹出,压回第一个栈中即可。

解法:

 import java.util.Stack;

 public class MyQueue
 {
     private Stack<Integer> inputStack;
     private Stack<Integer> outputStack;

     public MyQueue()
     {
         inputStack = new Stack<>();
         outputStack = new Stack<>();
     }

     public void push(int x)
     {
         while(!outputStack.isEmpty())
             inputStack.push(outputStack.pop());
         inputStack.push(x);
         while(!inputStack.isEmpty())
             outputStack.push(inputStack.pop());
     }

     public void pop()
     { outputStack.pop(); }

     public int peek()
     { return outputStack.peek(); }

     public boolean empty()
     { return outputStack.isEmpty(); }
 }

LeetCode 232 Implement Queue using Stacks的更多相关文章

  1. Leetcode 232 Implement Queue using Stacks 和 231 Power of Two

    1. 232 Implement Queue using Stacks 1.1 问题描写叙述 使用栈模拟实现队列.模拟实现例如以下操作: push(x). 将元素x放入队尾. pop(). 移除队首元 ...

  2. [LeetCode] 232. Implement Queue using Stacks 用栈来实现队列

    Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...

  3. (easy)LeetCode 232.Implement Queue using Stacks

    Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of ...

  4. Java [Leetcode 232]Implement Queue using Stacks

    题目描述: Implement the following operations of a queue using stacks. push(x) -- Push element x to the b ...

  5. Java for LeetCode 232 Implement Queue using Stacks

    Stack<Integer> stack=new Stack<Integer>(); public void push(int x) { stack.push(x); } // ...

  6. Leetcode 232 Implement Queue using Stacks STL

    本题用两个栈实现队列,用栈的基本操作去实现队列的所有基本操作push(),pop(),peek()以及empty() sa作为输入栈,sb作为输出栈,将sa输入元素的反转过来放到sb中 push与sa ...

  7. LeetCode 232 Implement Queue using Stacks 两个栈实现队列

    class MyQueue { public: /** Initialize your data structure here. */ MyQueue() { } /** Push element x ...

  8. leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues

    155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...

  9. 232. Implement Queue using Stacks,225. Implement Stack using Queues

    232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...

随机推荐

  1. 转AOP 介绍

    来自:http://blog.csdn.net/a906998248/article/details/7514969 这篇也不错,详细介绍了CGLIP http://blog.jobbole.com/ ...

  2. iOSbase64

    ios中使用BASE64进行加密和解密的方法也很简单,可以直接用google-toolbox-for-mac的GTMBase64.h来实现google-toolbox-for-mac的对应地址如下: ...

  3. Android权限安全(11)内置计费相关安全要点

    内置计费相关安全要点 1.计费Server接口保密且Transiction 加密 (SSL) 2.仅允许配套的安全本地组件(通常是第三方付费sdk如支付宝)与计费Server通信,且安全本地组件负责与 ...

  4. oracle lsnrctl status|start|stop

    [oracle@redhat4 ~]$ lsnrctl status LSNRCTL for Linux: Version 11.2.0.1.0 - Production on 06-OCT-2015 ...

  5. [Codeforces137A]Postcards and photos(模拟)

    题目链接:http://codeforces.com/contest/137/problem/A 题意:一个人搬东西,每次只能搬相同的东西,最多只能搬相同的东西不超过5个.问最少搬多少次. 模拟就行了 ...

  6. jenkins mac slave 设置

    1.在jenkins上增加节点, 2,在mac系统中将ssh的服务打开在偏好设置- 互联网与无线 - 共享中 3,使用mac root用户修改sshd-config的鉴权方式 首先获取到root用户登 ...

  7. 最大流 Dinic + Sap 模板

    不说别的,直接上模板. Dinic+当前弧优化: struct Edge{ int x,y,c,ne; }e[M*]; int be[N],all; int d[N],q[N]; int stack[ ...

  8. HDU 4906 状态压缩dp

    Our happy ending Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Other ...

  9. 英文 数字 不换行 撑破div容器

    我们在div等容器 中,如果规定了宽度,并且里面的内容不是全英文或者全数字是OK的,会自动换行,但是如果是全数字或者是全英文,则会撑破容器,如图     解决方法 word-wrap:break-wo ...

  10. ios tweak之binary not signed (use ldid -S)问题解决

    参考tweak教程写了个简单的tweak,无奈完全无效果,摸索了好长时间才找到方法: 打开terminal ssh root@192.168.1.100 vim /var/log/syslog 找到如 ...